The straight line is perpendicular to y = -3x + 4.
Therefore, the gradient of the straight line must be 3.
The equation of the straight line is y = 3x + 2.
Y=mx+b is slope intercept form. it is y=3x+2 where 3/1 is the slope and 2 is the y-intercept.
For b on the first paper you will start with the distribution property and multiply both x and 2 by 3 because they are in the ()
now you have 3x+ 6=x-18
from here you can subtract x from both sides
2x+6=-18
next subtract 6 from both sides
2x=-24
divide both sides by 2...
x=-12
hope this helped