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3 years ago

Find the slope of the line that passes through (-66, -21) and (-67, 20)

1 answer:

5 0

The straight line is given by the equation
y=kx+b
We substitute coordinates of points
-21=-66k+b (1)
2=-67k+b (2)
We give a system of equations
Solution of this system:
(1) b=66k-21
(2) 20=-67k+66k-21
20=-k-21
k=-21-20
k=-41
b=-41*66-21=-2727
y=-41x-2727

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What is the side length b in the triangle below

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12^2 +b^2 = 20^2 because of the Pythagorean theorem
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3 years ago

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Find the general solution of the given differential equation. x2y' + xy = 8 y(x) = give the largest interval over which the gene

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$x^2y'+xy=8$
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2 years ago

A limnologist wishes to estimate the mean phosphate content per unit volume of lake water. It is knownfrom studies in previous y

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Answer: 68

Step-by-step explanation:

As per given , we have

Population standard deviation : $\sigma=4$

Critical value for 90% confidence interval = $z_{\alpha/2}=1.645$

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$n=(\dfrac{z_{\alpha/2}\ \sigma}{E})^2$

i.e. $n=(\dfrac{(1.645)(4)}{0.8})^2=(8.225)^2$

$=67.650625\approx68$

Hence, the limnologist must analyze 68 samples.

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3 years ago

2sin^2x + 2cos^2x = 4a, then a = ? A. 4 B. 3 C. 2 D. 1 E. 1/2

tensa zangetsu [6.8K]

Answer:

E. 1/2

Step-by-step explanation:

Divide by 2, then make use of the Pythagorean identity for sine and cosine.

sin(x)^2 +cos(x)^2 = 2a

1 = 2a . . . . . . . sin²+cos²=1

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arlik [135]

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