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tankabanditka [31]
3 years ago
6

Y’all I need help on #9

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

8° = y

12° = x

________________

11° = z

7° = y

23 = x

Step-by-step explanation:

<u>What</u><u> </u><u>you</u><u> </u><u>need</u><u> </u><u>to know</u>

- m∠K ≅ m∠W; KB = WM

- m∠G ≅ m∠T; KG = WT

- m∠B ≅ m∠M; GB = TM

45° = [4x - 3]°

+ 3° + 3°

____________

\frac{48°}{4°} = \frac{[4x]°}{4°} \\ \\ 12° = x

Then use the Triangular Interior Angles Theorem to find the m∠Mthen set that equal to the m∠B:

180° = 41° + 45° + m∠M

180° = 86° + m∠M

- 86° - 86°

______________

94° = m∠M

94° = [11y + 6]°

- 6° - 6°

__________

\frac{88°}{11°} = {[11y]°}{11°} \\ \\ 8° = y

_______________________________________________

<u>What</u><u> </u><u>you</u><u> </u><u>need</u><u> </u><u>to know</u>

- m∠H ≅ m∠S; HC = SP

- m∠F ≅ m∠R; CS = RP

- m∠C ≅ m∠P; HF = SR

90° = [13y - 1]°

+ 1° + 1°

______________

\frac{91°}{13°} = \frac{[13y]°}{13°} \\ \\ 7° = y \\ \\ 90° = m∠R

Then use the Triangular Interior Angles Theorem to find the m∠Sthen set that equal to the m∠H:

180° = 28° + 90° + m∠S

180° = 118° + m∠S

- 118° - 118°

______________

62° = m∠S

62° = [6z - 4]°

+ 4° + 4°

____________

\frac{66°}{6°} = \frac{[6z]°}{6°} \\ \\ 11° = z

I am joyous to assist you anytime.

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Step-by-step explanation:

The second part of the function definition applies when x=0.

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  h(0) = 0 + 0 + 10 = 10

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The third part of the function definition applies when x=4.

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How is the vertex related to the maximum or minimum of a parabola?
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2x+3y=1 and y=-2 - 9 solve using linear combination method. Please explain steps.
kaheart [24]

Answer:

x=17

Step-by-step explanation:

2x+3y=1

y=-2-9

  • In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, y. In this case, we need to isolate y in the first equation so that both equations =y.

2x+3y=1

3y=-2x+1

\frac{3y}{3}=\frac{-2x+1}{3}

y=-\frac{2}{3}x+\frac{1}{3}

  • With this, we now know that both -2-9 and -\frac{2}{3}x+\frac{1}{3} are equal to y, so we can set them equal to each other.

y=-\frac{2}{3}x+\frac{1}{3}

y=-11

-\frac{2}{3}x+\frac{1}{3}=-11

  • Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for x.

-\frac{2}{3}x+\frac{1}{3}=-11

-\frac{2}{3}x=-11-\frac{1}{3}

-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}

-\frac{2}{3}x =-\frac{34}{3}

-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})

x=\frac{102}{6}=17

x=17

  • Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.

 

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