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Zepler [3.9K]
3 years ago
11

What is the least common denominator of 8/9 + 4/7?

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0
You have to find lcd so, 7x9=63 9x7=63, so the answer is 12/63, after you simplify it is 4/21
SVEN [57.7K]3 years ago
7 0
Do you mean LCM (Least common multiple)
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A store prices tapes by raising the wholesale price 50% and adding 25 cents .What must a tape's wholesale price be if the tape s
Andre45 [30]

Let's call the store value as s and the wholesale price as w. A store prices tapes by raising the wholesale price 50%(0.5 in decimals) and adding 25 cents, writing this as an equation, we have

s(w)=w+0.5w+0.25

If we invert the equation we're going to find the the wholesale price as a function of the store price.

\begin{gathered} s=w+0.5w+0.25 \\ s=1.5w+0.25 \\ s-0.25=1.5w \\ w(s)=\frac{s-0.25}{1.5} \end{gathered}

Now, to find the wholesale price if the sales price is $1.99, we just need to evaluate s = 1.99 on the function we created.

w(1.99)=\frac{1.99-0.25}{1.5}=1.16

The wholesale price is $1.16.

5 0
1 year ago
-13 times the difference between a number and 60 is equal to the number plus -59
kipiarov [429]
Let n represent the number.
  -13×(n -60) = n +(-59)
  -13n +780 = n -59
  839 = 14n
  839/14 = n = 59 13/14

The number is 59 13/14.

_____
Check
  The difference between the number and 60 is
    59 13/14 -60 = -1/14
  -13 times that value is
    -13*(-1/14) = 13/14
  Compare that to the number plus -59
    59 13/14 -59 = 13/14 . . . . . the same value, as required.
8 0
3 years ago
Please help me I would really appreciate it.
Karo-lina-s [1.5K]

Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

Proof:

In \Delta CDA\text{ and } \Delta ABC,

\overline{AB}\cong \overline {CD} because Given

\overline{BC}\cong \overline {DA} because Given

\overline{AC}\cong \overline {AC} because Reflexive property.

Corresponding sides of both triangles are congruent. So,

\Delta CDA\cong \Delta ABC because SSS

Therefore, the required missing values are: Given, \overline{BC}\cong \overline {DA}, Reflexive property ,\Delta CDA\cong \Delta ABC, SSS respectively.

5 0
2 years ago
S=L−rL<br><br> solve for r<br><br> Please solve this fast for much points.
podryga [215]
Subtract L from both sides. 
the expression now becomes,
<span>S−L=−rL</span>
2)Divide by L on both sides.
<span><span><span>S−L</span>L</span>=−r</span>
3)Multiply with a negative sign on both sides in the final step to obtain the expression in terms of r      so the answer is<span> #(L-S)/L = r#</span>
3 0
3 years ago
A hardware store receives shipments containing 600 light bulbs each.**Part A sample of 75 light bulbs in a given shipment contai
ollegr [7]

Answer:

24/600

Step-by-step explanation:

it may be wrong

6 0
2 years ago
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