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lozanna [386]
3 years ago
12

Kevin plants a total of 72 flowers in equal rows he plants 6 rows of yellow flowers and 2 rows of red flowers how many flowers a

re in each row
Mathematics
1 answer:
katovenus [111]3 years ago
5 0

Answer:

For red: 18 in each row. For yellow: 6 in each row

Step-by-step explanation:

72 flowers/equal amount= 36 flowers each color 36/2 red (rows)=18 36/6=6 yellow

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write the slope- intercept form of the equation of the line parallel to - x+5y=25, passing through the point (-5,-5). simplify
Olenka [21]
To find the equation of a line that is parallel to your original equation and goes through a certain point on a graph, here's what you need to know:
First you need to find the slope of your original equation.
To do that, you need to convert it to slope intercept form (y = mx+b).
Add the x over, and then divide everything by 5 to get the y by itself.
Here's what that would look like (without the small steps that I mentioned):
-x + 5y = 25
5y = x + 25
y = 1/5x + 5

That's the original equation rewritten in slope intercept form.
The m represents the slope, so this equation's slope is 1/5.

Because you are given a point, and now you have a slope, the best and easiest route is using point slope form.
I've seen different versions of the equation base but I prefer y - y(sub1) = m(x - x(sub1))
But since I can't use subscripts in this, I'll use the one with h and k. The h is the x value of the point, and the k is the y value.
(h,k)
Then just substitute the values in and solve for y.
y - k = m(x - h)
y + 5 = 1/5(x + 5)
y + 5 = 1/5x + 1
y = 1/5x - 4

Your final answer is
y = 1/5x - 4
You can double check by using a graph. If the slopes are the same, the lines should be parallel.

I hope that helps. If anything didn't make sense, feel free to ask me.
5 0
3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
Can someone pls help me . Thank you .
Pavel [41]
Answer:
1). 24
2). 8

Explanation:
1).

285$ - 45$ = 240$
240$/10 = 24$

Therefore, he pays 24$ a month.

2).
Let x be the number than triple:

3x - 5 = 19
3x = 19 + 5
3x = 24
x = 24/3
x = 8
5 0
3 years ago
Macy is making a border out of strips of wall boarder placed end to end along the 12-foot wall in her room. Each strip is foot l
slavikrds [6]
3 for each wall so the totally is 12
4 0
3 years ago
Evaluate the expression when a=-3 and x=3.<br> 5x - a
NISA [10]
5(3)-(-3)
15- (-3)
15+3 = 18
8 0
3 years ago
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