Answer:
Bl^2+4Bl*Fh
Step-by-step explanation:
I'm not quite certain what "draw a net" means here. But for part b, we are doing the formula. The bottom part is a square(assumingly so take this with a grain of salt), thus making the base equal to 3*3 cm or 9 cm^2. The triangular faces are each 3*2.24 cm or 6.72 cm^2. We then multiply this by 4 to get 26.88. Thus, the equation is Bl^2(Base length squared)+Bl*Fh(Face height, I forgot the official name sorry about that)*4 for part b.
Answer:
B. Perimeter of a square and
C. Side length of a square
Step-by-step explanation:
if n= side length of square then
- Area of square is

- Perimeter of a square is 4×n
- diagonal length of a square is
× n
Thus,
Perimeter of square can be expressed as
×diagonal length of a square
Side length of a square can be expressed as
×diagonal length of a square
but Area of square is
×n×diagonal length of a square
As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>
Answer:
-5
Step-by-step explanation:
15=-x+10
x-10=-15
x=-15+10
x=-5
Answer:
y = 
Step-by-step explanation:
Squaring a number means multiplying the number by itself. 0*0=0. 1*1=1. 2*2=4, and 3*3=9. This is the pattern shown in the table.
Answer: Circle A, EF is a minor Arc, EAD = 45 degrees, Arc EF= 150 Degrees, and FCE = 210 I guess from the looks of the Picture.
Step-by-step explanation: