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USPshnik [31]
3 years ago
10

Chapter 7 exstra review

Mathematics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

Give me a problem and I'll give you an answer. You didn't give a link the what your looking for.

Step-by-step explanation:

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Solve the simultaneous equation:<br> 5 x + 2 y = 25 <br> 5 x − y = 10
Liono4ka [1.6K]

Answer:

(x, y) = (3, 5)

Step-by-step explanation:

5x+2y=25\\5x-y=10

Solving by elimination here again, there are 2 good options available. Either multiply the whole bottom equation by -1 to cancel the x, or by 2 to cancel the y. I'll do the latter:

5x+2y=25\\\\2(5x-y=10)\\10x-2y=20

Add from top to bottom:

\rightarrow (5x+10x)+(2y-2y)=25+20\\\rightarrow 15x=45\\\rightarrow x=3

Now, with the value of x, solve for y in either of the equations. I'll choose the second one here:

\rightarrow 5x-y=10\\\rightarrow 5(3)-y=10\\\rightarrow 15-y=10\\\rightarrow -y=-5\\\rightarrow y=5

(x, y) = (3, 5)

4 0
2 years ago
Read 2 more answers
What is the following product?
KiRa [710]

ANSWER

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

EXPLANATION

The given product is:

( \sqrt{14}  -  \sqrt{3} )( \sqrt{12} +  \sqrt{7}  )

We expand using the distributive property to obtain:

\sqrt{14}( \sqrt{12} +  \sqrt{7}) -\sqrt{3}( \sqrt{12} +  \sqrt{7}  )

Extract the perfect squares to get:

\sqrt{14}(2 \sqrt{3} +  \sqrt{7}) -\sqrt{3}( 2\sqrt{3} +  \sqrt{7}  )

Expand further to get;

2 \sqrt{42} +7  \sqrt{2}- 2(3)   - \sqrt{21}

This simplifies to,

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

5 0
3 years ago
The formula for the cost of buying a car=
svet-max [94.6K]
8000-2600=5400
5400/12=450
monthly pavement =450
12x450+2600=8000
5 0
3 years ago
(9x+13)^2=49<br> Solve the quadratic equation given below.
Varvara68 [4.7K]

Answer:

x=(-2/3)

Step-by-step explanation:

(9x+13)^2=49

√(9x+13)^2=√49

9x+13=7

9x+13-13=7-13

9x=-6

9x÷9=-6/9

x=-6/9

-6/9=-2/3

3 0
3 years ago
What is the greatest common factor of 30 and 50
siniylev [52]

Hi,

The greatest common factor of 30 and 50 is 10.

Have a great day!


5 0
3 years ago
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