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maw [93]
3 years ago
11

The method used to factor trinomials of the form ax^2+bx+c can also be used to factor binomials of the form px^2+q by realizing

that, in this case, _____. A. a = 0 B. b = 0 C. c = 0 D. x = 0
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0
I think the best answer to your question is letter B. B=0. in the first trinomial factor of a form ax^2+bx+c is where the both variable values are not zero or having a positive or negative value which could make it possible to be factor off. While the second function px^2+q is the data that should be assigned into B is canceled out because its value is Zero.
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Answer:

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Step-by-step explanation:

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3 years ago
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Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

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The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

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