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wlad13 [49]
3 years ago
10

(3^n*3^2)^4=3^28 Enter the value of n for the equation N= ?

Mathematics
1 answer:
maksim [4K]3 years ago
8 0
Hello! And thank you for your question!

Use Pemdas to get

3^(n+2)*4=3^28

Rewrite the equation:

3^4(n+2) = 3^28

Cancel the base of 3:

4(n + 2) = 28

Then divide 4 on both sides:

2 + n = 28/4

Simplify 28/4:

2 + n = 7

Subtract 2 on both sides:

n = 7 - 2

Finally simplify 7 - 2:

n = 5

Final Answer:

n = 5
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