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2 years ago

Enrique collects miniature cars. He has one large case that holds 20 cars and 3 same-size, smaller cases to hold his cars.

Mathematics

1 answer:

dedylja [7]2 years ago

3 0

Answer:

C = 3n + 20

Step-by-step explanation:

There is one large case with 20 cars and 3 small cases with n cars in each.

Possible number of cars C is:

C = 3n + 20

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Evaluate p/2-5 when p=14

Dovator [93]

Answer:

$- 4.67$

Step-by-step explanation:

$\frac{p}{2 - 5} = \frac{14}{2 - 5} = \frac{14}{ - 3} = - 4.67$

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3 years ago

Factor 64v^3 + 192v^2 -56v - 168

Kaylis [27]

Hello from MrBillDoesMath!

Answer:

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )

Discussion:

Given

64v^3 + 192v^2 - 56 v - 168

Factor 64v^2 from the first two terms. Factor 56 from the last two terms:

64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms

(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()

8(v+3)(8v^2-7) => factor 8y^2-7

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )

Thank you,

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3 years ago

The ratio of the area to the circumference is A. 2r B.r/2 C. 2/r

weqwewe [10]

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lawyer [7]

Answer:

It has the same domain as the function $f(x)=-\sqrt{-x}$

Step-by-step explanation:

we have

$f(x)=\sqrt{-x}$

we know that

The radicand cannot be a negative number

$-x\geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain of the given function is the interval ----> (-∞,0]

All real numbers less than or equal to 0

The range of the given function is the interval ----> [0,∞)

All real numbers greater than or equal to zero

Verify each statement

Part 1) It has the same domain as the function $f(x)=-\sqrt{-x}$

The statement is true

The domain of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 2) It has the same range as the function $f(x)=-\sqrt{-x}$

The statement is false

The range of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 3) It has the same domain as the function $f(x)=-\sqrt{x}$

The statement is false

The domain of the function $f(x)=-\sqrt{x}$ is

the interval ---> [0,∞)

Part 4) It has the same range as the function $f(x)=-\sqrt{x}$

The statement is false

The range of the function $f(x)=-\sqrt{x}$ is

the interval ---> (-∞,0]

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