1. F(3)= -2(3)-5
-6-5
F(3)=-11
2. F(3)= -2(3)^2-4
-6^2-4
36-4
F(3)=32
3. F(x)=−2x−5
For: x=−2, f(x) is:f(−2)=(−2×−2)−5=4−5=−1
For: x=−1, f(x) is:f(−1)=(−2×−1)−5=2−5=−3
For: x=1, f(x) is:f(1)=(−2×1)−5=−2−5=−7
For: x=2, f(x) is:f(2)=(−2×2)−5=−4−5=−9
The Range is:
{−1,−3,−7,−9}
4. -80, -110
(0.5,2)
0.5 is x value
2 is y value
l
l
---------------
l
l
x value is on dashed line (0.5)
y value is on more separated line going up and down. (2)
To plot 0.5, you can put it as an equation. 0.5= 1/2. So to plot it, 0.5 is half of 1. So plot it as in between the 1 and 0.
To plot 2 go up to the two on the y axis and then go over 0.5 and plot a point.
That is you're plotted point for (0.5,2)
Hope it helps!
Answer:
Catherine's sister ate 2/15 gallons of the ice cream.
.
Step-by-step explanation:
Let 
be the amount of ice cream that Catherine's sister ate, in gallons.
- Original amount: 1 gallon.
- What Catherine ate:
gallons. - What Catherine's sister ate is assumed to be gallons.
- What's left:
gallons.
Consider the relationship:
.
That is:
.
Add to both sides of this equation:
Substract from both sides:
.
Convert the denominator of all three numbers on the left-hand side to 
.
.
In other words, Catherine's sister ate gallons of the ice cream.
Answer:
Step-by-step explanation:
Given Data,
Q=23000 J
c=4.184 J/g °c
Δt= 68 °c
m=?
By using this equation,
Q=mcΔt
A: because "reflection across the y axis then across the x axis is the only option that does not work"
