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natita [175]
3 years ago
11

PLEASE HELP ME!Food webs - transferring energy and matter from one level to another. Consider the food web you see here. Would y

ou change this food web to make it more accurate? If yes, how?
A) The food web is correct as is. I would not change anything.
B) Add the Sun; the source of energy. Add a decomposer also like fungi.
C) The food web is missing the decomposer. bacteria or fungi could be added.
Eliminate
D) The food web is missing the top level consumer. A predator must be

Mathematics
1 answer:
alexdok [17]3 years ago
5 0
The Answer Is B, Add The Sun;The Source Of Energy.Add A Decomposer Also Like Fungi. Hope This Helps!
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Four polynomials are shown below:
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Both B and D are 3rd degree, but only D is a 3rd degree binomial because it has only 2 terms. The answer is D.
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3 years ago
Let HH represent the number of hummingbirds and SS represent the number of sunbirds that must pollinate the colony so it can sur
Nikitich [7]

Answer: 7

Step-by-step explanation:

Here the given inequality that shows the number of humming birds(H) and the number of sunbirds(S)  that must pollinate the colony so it can survive until next year,

6 H + 4 S > 74

If This year, 8 hummingbirds pollinated the colony.

By putting H=8 in the above inequality,

We get,

6× 8 + 4 S > 74

⇒ 48 + 4 S > 74

⇒ 4 S > 26

⇒ S > 6.5

Hence the least number of sunbirds is 7.

7 0
3 years ago
Read 2 more answers
Write an equation of a line that is parallel to x=8 and that passes through the point (-3,-2)
alukav5142 [94]
The answer is 22 because you have 8 then you multiply 3 that gives you 24 then you subtract 2 and that. gives. you 22
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3 years ago
Write and expression to represent the submarines elevation after its final dive
Mama L [17]
Answer is in file explain: sorry if I’m wrong
5 0
3 years ago
Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}

3 0
3 years ago
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