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nekit [7.7K]
1 year ago
7

Can dilations be used to form scale copies of a figure?

Mathematics
1 answer:
Inessa [10]1 year ago
3 0

Answer:

sometimes

Step-by-step explanation:

There are several ways that dilation is used in real life. Here are several:

In graphic design. I actually do some graphic design, and I use dilation a lot. It is common to dilate photos to fit the space that you want it to fit.

In police work and crime investigation. Detectives and police dilate photos to see smaller details and evidence.

In architecture. It is normal for architects to make a prototype of their design or building. In order to make the building true to the prototype, they must dilate the scale and measurements.

In the doctor's office. Dilation is used in eye exams so that the eye doctor can view the patient's eye better. After a while it will slowly reduce in size and return back to normal.

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Matchhhhhh themmmmmmmmmm?
umka21 [38]

Answer:

My answer

Step-by-step explanation:

Matching the two set of variables:

1) Contains two outliers

2) Contains no outliers

3) Contains one outlier

4) Contains three outliers

7 0
2 years ago
8)Solve and rewrite using the distributive property __(__+__) = 12 +24​
Alla [95]

The distributive property will give answer 2 ( 6 + 12 ) = 12 + 24 .

The distributive law of multiplication over basic arithmetic such as addition and subtraction is known as distributive property .

According to this property , multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the no . and then adding the products together .

In other words, according to the distributive property, an expression of the form A ( B + C ) can be solved as A ( B + C ) = AB + AC.

2 ( 6 + 12 ) = 12 + 24 .

Hence , the distributive property will give answer 2 ( 6 + 12 ) = 12 + 24 .

To know more on distributive property follow link :

brainly.com/question/2807928

#SPJ9

6 0
1 year ago
What is the following product?
KiRa [710]

ANSWER

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

EXPLANATION

The given product is:

( \sqrt{14}  -  \sqrt{3} )( \sqrt{12} +  \sqrt{7}  )

We expand using the distributive property to obtain:

\sqrt{14}( \sqrt{12} +  \sqrt{7}) -\sqrt{3}( \sqrt{12} +  \sqrt{7}  )

Extract the perfect squares to get:

\sqrt{14}(2 \sqrt{3} +  \sqrt{7}) -\sqrt{3}( 2\sqrt{3} +  \sqrt{7}  )

Expand further to get;

2 \sqrt{42} +7  \sqrt{2}- 2(3)   - \sqrt{21}

This simplifies to,

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

5 0
2 years ago
Evaluate expression 20+3c+17d when c=8 and d=2.
Tems11 [23]
Just plug in the numbers for the variables.


20+3(8)+17(2)=
3 0
3 years ago
The total number of items sold by each student who participated in the fundraiser is showing in the stem and leaf plot
kenny6666 [7]

The statement that is best supported by the data in the stem and leaf plot is D. The most common number of items sold is 15.

<h3>How to illustrate the information?</h3>

It should be noted that the stem and plot diagram is important to illustrate the data given.

Based on the information given, the most common number of items sold is 15.

In conclusion, the correct option is D.

Learn more about stem plot on:

brainly.com/question/23450543

#SPJ1

The total number of items sold by each student who participated in a fund-raiser is shown in the stem and leaf plot.

Which statement is best supported by the data in the stem and leaf plot?

The number of students who sold between 10 and 20 items is greater than the number of students who sold more then 40 items.

The number of students who sold more than 30 items is greater than the number of students who sold fewer than 30 items.

The most common number of items sold is 30.

The most common number of items sold is 15.

4 0
1 year ago
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