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1 year ago

Can dilations be used to form scale copies of a figure?

Mathematics

1 answer:

Inessa [10]1 year ago

3 0

Answer:

sometimes

Step-by-step explanation:

There are several ways that dilation is used in real life. Here are several:

In graphic design. I actually do some graphic design, and I use dilation a lot. It is common to dilate photos to fit the space that you want it to fit.

In police work and crime investigation. Detectives and police dilate photos to see smaller details and evidence.

In architecture. It is normal for architects to make a prototype of their design or building. In order to make the building true to the prototype, they must dilate the scale and measurements.

In the doctor's office. Dilation is used in eye exams so that the eye doctor can view the patient's eye better. After a while it will slowly reduce in size and return back to normal.

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the students at walden middle school are selling tins of popcorn to raise money for new uniforms. They sold 42 tins in the first

zubka84 [21]

Answer:

Step-by-step explanation:

It’s 2828292949.0 bc ik I had the answer key

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3 years ago

Sum of interior angles find measure angle BCA

AURORKA [14]

Answer:

d) 76

Step-by-step explanation:

there are 180 degrees inside a triangle

so, 40+(3x+10)+(2x+20) = 180

combine 'like terms' to get:

5x + 70 = 180

subtract 70 from each side to get:

5x = 110

divide each side by 5:

x = 22

m∠BCA = 3(22)+10

= 66+10

= 76°

8 0

2 years ago

1 For each of the following two linear equations identify the slope and the 3y+ x= 12

ahrayia [7]

For identifying the slope of a line, is easier if we get the equation to its slope-intercept form, that is:
y = mx + b
where m is the slope, and b is the y axis intercept. So we'll change the original equations and get them to this form:

3y+ x= 12
3y = -x + 12
y = (-1/3) + 4
therefore the slope is -1/3 and the y-axis intercept is 4

-9x + 4y = 16
4y = 9x + 16
y = (9/4)x + 4
therefore the slope is 9/4 and the y-axis intercept is 4

7 0

2 years ago

Read 2 more answers

What is the interquartile range of the data set? 94 60 110 120 140

KonstantinChe [14]

The interquartile range is the difference between the first quartile 77 and the third quartile 130. In this case, the difference between the first quartile 7777 and the third quartile is 130−(77)130-(77).130−(77)130-(77)Simplify 130−(77)130-(77) to get 53
Answer is 53

8 0

3 years ago

The base of a triangle is twelve more than twice its height. If the area of the triangle is 51 square centimeters, find its bas

Anarel [89]

The base and height of the triangle whose area is 51 $cm^2$ and base of a triangle is twelve more than twice its height are 21.49 cm and 4.745 cm respectively.

Solution:

Given that

The base of a triangle is twelve more than twice its height

And area of triangle = 51 square centimeter

Let’s assume height of triangle = "x" cm

So base of triangle = 12 + (2 $\times$ height ) = 2x + 12

$\text { Area of triangle }=\frac{1}{2} \times \text { Base } \times \text { height }$

On substituting the given value of area and assumed values of height and base in above formula we get

$\begin{array}{l}{51=\frac{1}{2} \times(2 x+12) \times x=x^{2}+6 x} \\\\ {\Rightarrow x^{2}+6 x-51=0}\end{array}$

We can find solution of this equation using quadratic formula.

According to quadratic formula for general equation $\mathrm{ax}^{2}+\mathrm{b} x+\mathrm{c}=0$ solution of the equation is given by

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Our equation is $x^{2}+6 x-51=0$

So in our case, a = 1 , b = 6 and c = -51

On applying quadratic formula we get

$\begin{array}{l}{x=\frac{-6 \pm \sqrt{6^{2}-(4 \times 1 \times(-51))}}{2 \times 1}} \\\\ {x=\frac{-6 \pm \sqrt{36+204}}{2}} \\\\ {x=\frac{-6 \pm \sqrt{240}}{2}} \\\\ {x=\frac{-6 \pm \sqrt{240}}{2}=\frac{-6 \pm 15.49}{2}}\end{array}$

$=>x=\frac{-6+15.49}{2} \text { or } x=\frac{-6-15.49}{2}$

As dimensions of triangle cannot be negative so neglect negative value

$x=\frac{-6+15.49}{2}=\frac{9.49}{2}=4.745$

Height of triangle = x = 4.745 cm

Base of triangle = 12 + ( 2 x 4.745 ) = 12 + 9.49 = 21.49 cm

Hence base and height of the triangle whose area is 51 $cm^2$ and base of a triangle is twelve more than twice its height are 21.49 cm and 4.745 cm respectively.

3 0

2 years ago