Answer:
0.0838 (8.62%)
Step-by-step explanation:
defining the event G= an out-of-state transaction took place in a gasoline station , then the probability is
P(G) = probability that the transaction is fraudulent * probability that took place in a gasoline station given that is fraudulent + probability that the transaction is not fraudulent * probability that took place in a gasoline station given that is not fraudulent = 0.033 * 0.092 + 0.977 * 0.034 = 0.0362
then we use the theorem of Bayes for conditional probability. Defining also the event F= the transaction is fraudulent , then
P(F/G)=P(F∩G)/P(G) = 0.033 * 0.092 /0.0362 = 0.0838 (8.62%)
where
P(F∩G)= probability that the transaction is fraudulent and took place in a gasoline station
P(F/G)= probability that the transaction is fraudulent given that it took place in a gasoline station
Answer:y=3x+6
Step-by-step explanation:
Answer:
y = 23
Step-by-step explanation:
The diagonals of a rhombus are perpendicular bisectors of each other, thus
∠1 = 90° and ∠1 = 4y - 2, so equating gives
4y - 2 = 90 ( add 2 to both sides )
4y = 92 ( divide both sides by 4 )
y = 23
