V=hpir^2
c=2pir
assuming they havve same height
first one is
v=hpi5^2
v=25hpi
2nd one
c=2pir=20pi
2pir=20pi
2r=20
r=10
v=hpir^2
v=hpi10^2
v=100hpi
big/small=100hpi/25hpir=4
4 times greater
Answer:
All real numbers are solutions
Step-by-step explanation:
Let's solve your equation step-by-step
3(x+2)=5x+1−2x+5
Step 1: Simplify both sides of the equation
3(x+2)=5x+1−2x+5
(3)(x)+(3)(2)=5x+1+−2x+5(Distribute)
3x+6=5x+1+−2x+5
3x+6=(5x+−2x)+(1+5)(Combine Like Terms)
3x+6=3x+6
3x+6=3x+6
Step 2: Subtract 3x from both sides
3x+6−3x=3x+6−3x
6=6
Step 3: Subtract 6 from both sides
6−6=6−6
0=0
1. No answer ( may be due to incorrect question)
2. x = -3
y = 4
3. x= 4
y = 2
4.x = -63/40
y= -19/20
Step 1
Multiply equation 1 by the coefficient of x in equation 2
Multiply equation 2 by the coefficient of x I'm equation 1
(after completing this step you will derive equation 3 and 4 )
Step 2
Subtract equation 4 from equation 3
Step 3
Divide both sides of the equation by the coefficient of y
Step 4
substitute your value for y in equation 1 or 2
(after this you will derive the values of x)
Note : This method is for the Elimination of x
I hope it helps