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3 years ago

(70 points)

2 answers:

meriva3 years ago

8 0

$f(x) = -0.26x^2 + 1.2x + 5.7\\\\\\f'(x)=(-0.26x^2 + 1.2x + 5.7)'=(-0.26x^2)'+(1.2x)'+(5.7)'=\\\\=-0.26(x^2)' + 1.2(x)' + (5.7)'=-0.26\cdot(2x) + 1.2\cdot1+0=\\\\=\boxed{-0.52x+1.2}$

Answer C)

hram777 [196]3 years ago

5 0

f(x) = -0.26x^2 + 1.2x + 5.7

differentiate by x

f'(x) = -0.26*2x + 1.2

= -0.52x + 1.2

ans is C

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Explanation:
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Given the quadratic function:
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→ " y = (x − 8) (x + 3) " ; ← Note: Replace the "f(x)" with: "y" ;

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→ Note: The "y-intercept" is the coordinate of the point(s) of the graph of the equation at which the graph crosses the "x-axis" when "x = 0" .

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So, the "y -intercept" of the given quadratic function is:

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→ which is: Answer choice: [C]: " (0, - 24) " .
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