<h2>☸
<u>Solution</u><u>:</u></h2>
We have,
- Departing time = 10 : 45 hours
- Distance between home and airport = 325 km
- Average speed = 50 km/h
Finding time taken by the man,
⇛ Average speed = Total Distance/Total time
⇛ Total time = Total Distance/Average speed![.](https://tex.z-dn.net/?f=.)
⇛ Total time = 325 km/50 km/h
⇛ Total time = 6.5 h (6 hrs 30 mins)
(a) Total Time duration,
⇛ Total Time = Reaching Time - Departing time
⇛ 6.5 h = Reaching Time - 10 : 45 hours
⇛ Reaching Time = 17 : 15 hours ( 5 : 15 pm)
(b) Finding time taken in return,
- Departing time = 18 : 35 hours
- Reaching time = 23 : 10 hours
Total time duration,
⇛ Total Time = Reaching Time - Departing time
⇛ Total Time = 23 : 10 hours - 18 : 35 hours
⇛ Total Time = 22 : 70 hours - 18 : 35 hours
⇛ Total time = 4 : 35 hours
☕ Hence, solved !!
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Answer:
The value of p at q = 5 is 406.25
Step-by-step explanation:
∵ p varies directly as the cube of q
→ That means p ∝ q³
∴ The equation of variation is p = kq³, where k is the constant of variation
∵ p = 26 when q = 2
→ Use them to find the value of k
∵ 26 = k(2)³
∴ 26 = k(8)
∴ 26 = 8k
→ Divide both sides by 8
∴ ![\frac{26}{8}=\frac{k}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B26%7D%7B8%7D%3D%5Cfrac%7Bk%7D%7B8%7D)
∴ 3.25 = k
→ Substitute it in the equation of variation
∴ p = 3.25 q³ ⇒ equation of variation
∵ q = 5
→ Substitute it in the equation of variation to find p
∴ p = 3.25 (5)³
∴ p = 406.25
∴ The value of p at q = 5 is 406.25
Answer:
b
Step-by-step explanation:
Perimeter = 2(W+L) = 80
W + L = 40
W = 4
L = 36
so length = 36 cm