The length of the shorter rope is 20 cm.
<h3>How to find the original length of the rope using ratio?</h3>
He cut a rope into two pieces with lengths having a ratio of 5 to 2.
The shorter piece is 70 cm long.
The length of the original rope can be calculated as follows:
The ratio of the length of the rope is as follows;
5 : 2
let
x = length of the original rope
Therefore,
length of shorter piece = 2 / 7 × 70
length of shorter piece = 2 / 7 × 70
length of shorter piece = 140 / 7
length of shorter piece = 20 cm
Therefore, the length of the shorter rope is 20 cm.
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Y=a(x-h)^2+k
vertex form is basically completing the square
what you do is
for
y=ax^2+bx+c
1. isolate x terms
y=(ax^2+bx)+c
undistribute a
y=a(x^2+(b/a)x)+c
complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside
y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c
complete square
too messy \
anyway
y=2x^2+24x+85
isolate
y=(2x^2+24x)+85
undistribute
y=2(x^2+12x)+85
1/2 of 12 is 6, 6^2=36
add neagtive and postivie isnde
y=2(x^2+12x+36-36)+85
complete perfect square
y=2((x+6)^2-36)+85
distribute
y=2(x+6)^2-72+85
y=2(x+6)^2+13
vertex form is
y=2(x+6)^2+13
Answer:
shoes 324×2 =648
sandals 187×2 = 374
so 374 + 648 = 1022 shoes and sandal pairs
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5. Answer: see explanation
<u>Step-by-step explanation:</u>
If the roots are m and 3m, then x = m and x = 3m
⇒ x - m = 0 and x - 3m = 0
⇒ (x - m)(x - 3m) = 0
⇒ x² - 4mx + 3m² = 0
Since x² + px + q = 0 then p = -4m and q = 3m²
3p² = 3(-4m)² 16q = 16(3m²)
= 3(16m²) = 48m²
= 48m²
3p² = 48m² = 16q ⇒ 3p² = 16q
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6. Answer: 8 or 18
<u>Step-by-step explanation:</u>
The Area of the entire rectangle (A = L × w) is 12 × 10 = 120
The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.
There are two non-shaded triangles.
- Bigger non-shaded Δ: L = 12-x, w = 10 ⇒

- Smaller non-shaded Δ: L = x, w = x ⇒

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

Area of ΔBEF:

Answer:
A. W
Step-by-step explanation:
Because this is a rigid transformation, quadrilaterals WXYZ and ABCD are congruent. Corresponding parts of corresponding figures are congruent, so W is congruent to A and because we know the measure of angle A, you also know the angle measure of W.