Answer:
the heat of formation of isopropyl alcohol is -317.82 kJ/mol
Explanation:
The heat of combustion of isopropyl alcohol is given as follows;
C₃H₇OH (l) +(9/2)O₂ → 3CO₂(g) + 4H₂O (g)
The heat of combustion of CO₂ and H₂O are given as follows
C (s) + O₂ (g) → CO₂(g) = −393.50 kJ
H₂ (g) + 1/2·O₂(g) → H₂O (l) = −285.83 kJ
Therefore we have
3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ which we can write as
3C (s) + 3O₂ (g) → 3CO₂(g) = −393.50 kJ × 3 =
4H₂ (g) + 2·O₂(g) → 4H₂O (l) = −285.83 kJ × 4
3CO₂(g) + 4H₂O (g) → C₃H₇OH (l) +(9/2)O₂ = +2006 kJ/mol
-1180.5 - 1143.32 +2006 = -317.82 kJ/mol
Therefore, the heat of formation of isopropyl alcohol = -317.82 kJ/mol.
Answer:
30
Explanation:
atomic mass = proton number + neutron number
proton number is also atomic number
Answer:
jst do the work
Explanation:
its not complicated,ask your teacher for help
Answer: Shaun must consume 6 more g of protein to reach the required amount.
Explanation:
Given : Recommended amount of protein = 200 calories
Now 4 calories = 1 gram of protein
Thus 200 calories = 
g of protein.
Calories consumed per day by Shaun = 176 calories
176 calories = 
g of protein.
Thus Shaun need to consume = (50-44) g = 6 of protein to reach the required amount.
Shaun must consume 6 more g of protein to reach the required amount.
