Answer:
You will have 19.9L of Cl2
Explanation:
We can solve this question using:
PV = nRT; V = nRT/P
<em>Where V is the volume of the gas</em>
<em>n the moles of Cl2</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is 273.15K assuming STP conditions</em>
<em>P is 1atm at STP</em>
The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:
63g * (1mol / 70.906g) = 0.8885 moles
Replacing:
V = 0.8885mol*0.082atmL/molK*273.15K/1atm
V = You will have 19.9L of Cl2
Salts of Transition elements.
CuSO4
Answer:
3'700,000 cfu
Explanation:
One way to count the amount of bacteria in a medium is by doing a dilution of the sample and count how many colonies growth. Each colony is a cfu (Colony forming units).
In the problem, you count 37 colonies. The dilution was 1:100,000. That means the bacteria present in the soap is:
37 colonies × (100,000 / 1) = <em>3'700,000 cfu</em>
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I hope it helps!
In a phase diagram that I have attached, the line marked in between ice and water (yellow and blue) is the conditions in which solid (ice) and liquid (Water) can coexist. As the graph shows, solid ice and liquid water coexist most when the temperature is zero, which should make sense since ice melts at 0, and water freezes as well at 0 degrees celsius.