Ask question

Ask question

All categories

3 years ago

6

I AM GIVING BRAINLIEST! PLEASEEEEEE HELPPPPPP I NEED HELPPP

1 answer:

My name is Ann [436]3 years ago

5 0

Answer:

I think that the answer is N20:2(14.01)+1(16.06)=44.02g/mol(c) fluorine Di nitrogen monoxide contains how many mom 6.022 x

1023 mol N20

You might be interested in

To fine the number of neutrons in an atom, subtract its_____

storchak [24]

a is the answer hope this helps

3 0

3 years ago

What must happen for heat to be transferred by convection?

Inessa05 [86]

Answer: The heat transfer by convection requires a solid-fluid interface, a temperature difference between the solid surface and the surrounding fluid and a motion of the fluid. The process of heat transfer by convection would occur when there is a movement of macro-particles of the fluid in space from a region of higher temperature to lower temperature.

Mark as brainliest

6 0

2 years ago

If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is

laila [671]

Answer: .039L

Explanation:

8 0

2 years ago

Determine whether the following statement about equilibrium is true or false.

Lady_Fox [76]

Answer:

(a) when a reaction system reaches a state of equilibrium, the concentration of the products is equal to the concentration of the reactants

6 0

3 years ago

A 3.0-L sample of helium was placed in container fitted with a porous membrane. Half of the helium effused through the membrane

zhenek [66]

Explanation:

It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.

And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.

$\frac{1.5 L}{24 hr}$

= 0.0625 L/hr

As, molar mass of He is 4 g/mol and molar mass of $O_{2}$ is 32 g/ mol.

Now,

$\frac{\text{Rate of He}}{\text{Rate of Oxygen}} = \sqrt{\frac{32}{4}$

= 2.83

or, rate of $O_{2} = \frac{\text{Rate of He}}{2.83}$

= $\frac{0.0625 L/hr}{2.83}$

Rate of $O_{2}$ = 0.022 L/hr.

This means that 0.022 L of $O_{2}$ gas effuses in 1 hr

So, time taken for the effusion of 1.5 L of $O_{2}$ gas is calculated as follows.

$\frac{1.5 L}{0.022 L/hr}$

= 68.18 hour

Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.

3 0

3 years ago