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aliina [53]
3 years ago
15

−6>−30−4x help please

Mathematics
1 answer:
nikklg [1K]3 years ago
6 0

from both sides of the equation.

Answer:

Apply the distributive property.

6 ⋅ 5 + 6 (-3x) = -4 x - 12

Multiply

6 by 5 . 30 + 6 (-3 x) = - 4 x - 12

Multiply

− 3 by 6 . 30 - 18 x = - 4 x - 12

Add

4 x to both sides of the equation.

30 - 18 x + 4 x = - 12

Add

− 18 x and 4 x . 30 - 14 x = - 12

Subtract

30

from both sides of the equation.

- 14 x = - 12 - 30

Subtract

30 from

− 12 . - 14 x = - 42

x = 3

Step-by-step explanation:

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Mark and John share the sum of $40 in ratio 2:3 how much does John get​
lara [203]

Answer:

John gets 24 dollars

Step-by-step explanation:

Divide 40 into 5 because 2+3 equals 5.

Each "section" equals 8. Now, multiply that by 3(John's section)

You get 24.

4 0
3 years ago
If u go to sleep at 9:30 p.m. and wake up at 6:30a.m. The next morning how long did u sleep
puteri [66]
Well first do this
12.00 - 9.30 = 2.30
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8 0
3 years ago
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Type 500 words in 20 minutes<br><br><br> _______ words per minute
7nadin3 [17]

Answer:

25

Step-by-step explanation:

Divide 500/20

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3 years ago
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Find the distance between the points. (Round your answer to two decimal places. (9.7, - 2.8), (- 3.2, 8.8)
Dmitry [639]

Answer:

Rounding it to two decimal places, we get distance, d=17.35

Step-by-step explanation:

Given:

The two points are (9.7, -2.8)\textrm{ and }(-3.2, 8.8)

The distance between the two points can be obtained using the distance formula which is given as:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Here, for the points, (9.7, -2.8)\textrm{ and }(-3.2, 8.8)

x_{1}=9.7,x_{2}=-3.2,y_{1}=-2.8,y_{2}=8.8

Therefore, the distance between the points is:

d=\sqrt{(-3.2-9.7)^2+(8.8-(-2.8))^2}\\d=\sqrt{(-12.9)^2+(8.8+2.8)^2}\\d=\sqrt{(12.9)^2+(11.6)^2}\\d=\sqrt{166.41+134.56}\\d=\sqrt{300.97}=17.348

Rounding it to two decimal places, we get d=17.35

7 0
3 years ago
2.1 x 10^10 OVER 7 x 10^17
vlabodo [156]
2.1 x 10^10/ 7 x 10^17 
= 3 x 10^-8

hope this helps and have a great day :)


4 0
3 years ago
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