Hello from MrBillDoesMath
Answer:
[email protected] = - sqrt(7)/ 4
which is choice B
Discussion:
This problem can be solved by drawing triangles and looking at ratios of sides or by using the trig identity:
([email protected])^2 + (sin2)^2 = 1
If [email protected] = 3/4
, the
([email protected])^2 + (3/4)^2 = 1 => (subtract (3/4)^2 from both sides)
([email protected])^2 = 1 - (3/4)^2 = 1 - 9/16 = 7/16
So...... taking the square root of both sides gives
[email protected] = +\- sqrt(7)/ sqrt(16) = +\- sqrt(7)/4
But is [email protected] positive or negative? We are told that @ is in the second quadrant and cos(@) is negative in this quadrant, so our answer must be negative
[email protected] = - sqrt(7)/ 4
which is choice B
Thank you,
Mr. B
<h3>
Answer: approximately 6.3 miles</h3>
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Explanation:
See the diagram below. The two given angles B = 105 and C = 20 are used to help find angle A
A+B+C = 180
A+105+20 = 180
A+125 = 180
A = 180-125
A = 55
Then we use the law of sines to find the side length c
sin(A)/a = sin(C)/c
sin(55)/15 = sin(20)/c
c*sin(55) = 15*sin(20) ... cross multiply
c = 15*sin(20)/sin(55) .... divided both sides by sin(55)
c = 6.26294249724791 .... value is approximate
c = 6.3 ....... rounding to one decimal place
It would be Answer A) x>6
Answer:
So, option A is correct.
Step-by-step explanation:
To find the inverse of the matrix, the formula is:

Inverse of the matrix exists if |A| does not equal to 0
|A| = 7 * 9 -( -2 * -10)
|A| = 63 - 20
|A| = 43
AS |A| ≠ 0
so inverse exist.
now finding Adj A
= ![\left[\begin{array}{cc}9&2\\10&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%262%5C%5C10%267%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}9/43&2/43\\10/43&7/43\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%2F43%262%2F43%5C%5C10%2F43%267%2F43%5Cend%7Barray%7D%5Cright%5D)
So, option A is correct.