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docker41 [41]
3 years ago
15

solve The mean score of a competency test is 60, with a standard deviation of 5. Between what two values do about 68% of the val

ues lie? (Assume the data set has a bell-shaped distribution.
Mathematics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

Between 55 and 65

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 60

Standard deviation = 5

Between what two values do about 68% of the values lie?

By the Empirical Rule, within 1 one standard deviation of the mean. So from 60-5 = 55 to 60+5 = 75.

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Select the correct answer.
aleksklad [387]
We want 10% = 0.1 = $10
Then to work out 100% we divide $10 by 0.1
$10/0.1 = $100
6 0
4 years ago
Justin buys a shirt that costs 24 dollars and a jacket that costs 54 dollars. If sales tax is 7%, what is the total purchase pri
andreyandreev [35.5K]

Answer:

$83.46

Step-by-step explanation:

24 + 54 =78

78 × 7% = 5.46

78 + 5.46 = $83.46

8 0
3 years ago
One T-shirt is sold for every 5 people who attend a concert. What is one way to write the unit rate in words?
liraira [26]

Answer : the answer is 5 people per T-shirt

Step-by-step explanation: because its 5 people per 1 T-shirt

3 0
3 years ago
One number is 9 more than another. if the sum of the two numbers is 163​, find the two numbers.
tiny-mole [99]
I think that one number is 77 and the other is 86. 77 + 9 is 86. 86 +77 is 163.
5 0
3 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
3 years ago
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