Answer:
Because Saturn has a longer orbital period.
Explanation:
The length of seasons is not determined by axial tilt, but by orbital period. The seasons we define on Earth take a quarter of the orbital period (year) each. So, since our orbital period is of 12 months, each season takes 3 months. Saturn has an orbital period of about 29 years, so each season would take over 7 years.
Answer:
<h2>The answer is 9 W</h2>
Explanation:
The power used by an object can be found by using the formula
w is the workdone
t is time taken
From the question we have
We have the final answer as
<h3>9 W</h3>
Hope this helps you
Answer:
3.97 m/s
Explanation:
Speed is defined as the distance covered per unit time. Therefore, s=d÷t=d/t
Where d is distance and t is time
Given distance of 5 km and time of 21 minutes the speed would be given by dividing 5 km by 21 min. However, speed is expressed as km/h or m/s or miles per hour etc. So we nees to get our speed in one of these standard units.
Going for m/s
Conversion
1 km has 1000m hence
5 km=5*1000=5000m
1 min has 60 seconds hence
21 min=21*60=1260 s
Speed=5000m÷1260s=3.9682539682538 m/s
Rounded off, s=3.97 m/s
The magnitude of the current in wire 3 is (I₃)= 0.33A
<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>
To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,
I₁ + I₂ + I₃ = 0
Where we are given,
I₁ = current in wire 1
=0.40 A.
I₂ = current in wire 2
= -0.73 A.
We have to calculate the magnitude of the current in wire 3, I₃
Now we put the known values in above equation, we get,
I₁ + I₂ + I₃ = 0
Or, I₃ = -.(I₁ + I₂)
Or, I₃ = -.(0.40 - 0.73)
Or, I₃ = 0.33 A
From the above calculation, we can conclude that the current in wire 3 is I₃ = 0.33 A
Learn more about current:
brainly.com/question/25537936
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Answer:
They both have a reflection, but a mirror just reflects anything in front of it, while a magnifying glass helps you see closer through the reflection of something.
Explanation:
