Answer:
Q₁ > Qo
C₁ > Co
Explanation:
We know that

Lets take relative permitivity of green plate =k
So new capacitance value

From above two expression we can say that
C₁ = kCo
k > 1
So we can say that
C₁ > Co
We also know that
Co = Qo V
C₁ = Q₁ V
From above we can say that
Co/C₁ = Qo/Q₁ ( C₁ > Co ⇒Co/C₁ <1)
Co/C₁ <1
So we can say that
Qo/Q₁ < 1
Q₁ > Qo
So, the final velocity of the ball when it is 10.0 m above the ground approximately <u>26.2 m/s</u>.
<h3>Introduction</h3>
Hi ! In this question, I will help you. This question uses the principle of final velocity in free fall. Free fall occurs only when an object is dropped (without initial velocity), so the falling object is only affected by the presence of gravity. In general, the final velocity in free fall can be expressed by this equation :

With the following condition :
- v = final velocity (m/s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
<h3>Problem Solving</h3>
We know that :
= initial height = 45.0 m
= final height = 10.0 m- g = acceleration of the gravity = 9.8 m/s²
Note :
At this point 10 m above the ground, the object can still complete its movement up to exactly 0 m above the ground.
What was asked :
- v = final velocity = ... m/s
Step by Step






<h3>Conclusion</h3>
So, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.
<h3>See More :</h3>
Answer:
CONVEX
Explanation:
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