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Goshia [24]
3 years ago
10

A runner is jogging in a straight line at a

Physics
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer:

Total distance traveled by bird is 10.5 km.

Explanation:

Given that,

Velocity of runner= 8.4 km/hr

Distance = 6.3 km

Velocity of bird = 42 km/hr

Suppose, How far does the bird travel?

We need to calculate the time of bird

Using formula of time

t=\dfrac{d}{v_{b}}

Put the value into the formula

t=\dfrac{6.3}{42}

t=0.15\ hr

We need to calculate the distance runner travels during time period

Using formula of distance

d=v_{r}\times t

d=8.4\times0.15

d=1.26\ km

We need to calculate the distance of runner to FL

Using distance

d'=6.3-1.26

d'=5.04\ km

We need to calculate the net closing speed between runner and bird

Using speed

v'=v_{r}+v_{b}

v'=8.4+42

v'=50.4\ km/hr

We need to calculate the time for runner and bird to meet

Using formula of time

t=\dfrac{d}{v'}

Put the value into the formula

t=\dfrac{5.04}{50.4}

t=0.1\ hr

We need to calculate the distance covered by runner

Using formula of distance

d=vt

Put the value into the formula

d=8.4\times0.1

d=0.84\ km

We need to calculate the distance covered by bird to runner

Using formula of distance

d=vt

Put the value into the formula

d=42\times0.1

d=4.2\ km

We need to calculate the total distance

Using distance

D=6.3+4.2

D=10.5\ km  

Hence, Total distance traveled by bird is 10.5 km.

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Differentiate between angular displacement and linear displacement.​
Sauron [17]

Answer:

The angular displacement is not a length (not measured in meters or feet), so an angular displacement is different than a linear displacement. ... As the object rotates through the angular displacement phi, the point on the edge of the disk moves distance sa along a circular path.

7 0
3 years ago
According to the Law of Reflection, the angle of incidence
Elan Coil [88]

Answer:

A

Explanation:

this is because the law of reflection states that the angle of incidence equals to the angle of the reflection.

hope this helps, if not please report it

someone else can try it

8 0
3 years ago
The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s. (a) What
Neko [114]

Complete Question

The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s.

(a) What is its angular acceleration in revolutions per minute-squared

(b) How many revolutions does the engine make during this 20 s interval?

rev

Answer:

a

 \alpha = 6261 \  rev/minutes^2

b

 \theta  = 613 \ revolutions

Explanation:

From the question we are told that

   The initial  angular speed is w_i =  1120 \ rev/minutes

    The angular speed after t = 13.8 s = \frac{13.8}{60 }  = 0.23 \ minutes  is w_f = 2560 \ rev/minutes

    The time for revolution considered is t_r =  20 \ s  =  \frac{20}{60} = 0.333 \  minutes  

 Generally the angular acceleration is mathematically represented as

         \alpha = \frac{w_f - w_i }{t}

=>      \alpha = \frac{2560  - 1120 }{0.23}  

=>      \alpha = 6261 \  rev/minutes^2

Generally the number of revolution made is t_r =  20 \ s  =  \frac{20}{60} = 0.333 \  minutes  is mathematically represented as

           \theta  =  \frac{1}{2}  * (w_i + w_f)*  t

=>      \theta  =  \frac{1}{2}  * (1120+ 2560 )*  0.333

=>      \theta  = 613 \ revolutions

5 0
3 years ago
A light bulb has a power rating of 60 W. What is the current running into it if it is plugged into a 120 V outlet?
kifflom [539]

Answer:

0.5 Amperes

Explanation:

Information that we have:

Power: P=60W

Voltage: V=120V

and we use the equation that relates this two quantities to the Current (I):

I=\frac{P}{V}

where I is the curent, P is the Power and V is the Voltage.

we substitute the values given for the Power and the Voltage to find the current:

I=\frac{60W}{120V}\\ I=0.5A

the Current running into the bulb is 0.5 Amperes

3 0
3 years ago
Convert this number to standard notation: 1.4 x 10^-2*
Marysya12 [62]

Answer:

0.014

Explanation:

here

1.4 x 10^-2

=0.014

may this help

6 0
3 years ago
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