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NISA [10]
3 years ago
11

An automobile tire is rated to last for 60,000 miles. to an order of magnitude, through how many revolutions will it turn?

Physics
1 answer:
Nastasia [14]3 years ago
3 0

Let the average diameter of the automobile tire is about 2 feet. Therefore its circumference is  2 feet\times \pi =6.29 feet.

Now we have to convert an automobile tire is rated to last for 60,000 miles in to feet.

As 1 miles =5280 feet .

So, 60000 miles = 60000\times 5280 feet =316800000 feet

Thus the number of revolutions,

\frac{316800000 feet }{6.29 feet} =50365659.8 revolutions \\\\=5.0\times10^7 rev

Hence, order of magnitude of revolutions is 7.

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A series LRC circuit consists of a 12.0-mH inductor, a 15.0-µF capacitor, a resistor, and a 110-V (rms) ac voltage source. If th
finlep [7]

Answer:

61.85 ohm

Explanation:

L = 12 m H = 12 x 10^-3 H, C = 15 x 10^-6 F, Vrms = 110 V, R = 45 ohm

Let ω0 be the resonant frequency.

\omega _{0}=\frac{1}{\sqrt{LC}}

\omega _{0}=\frac{1}{\sqrt{12\times 10^{-3}\times 15\times 10^{-6}}}

ω0 = 2357 rad/s

ω = 2 x 2357 = 4714 rad/s

XL = ω L = 4714 x 12 x 10^-3 = 56.57 ohm

Xc = 1 / ω C = 1 / (4714 x 15 x 10^-6) = 14.14 ohm

Impedance, Z = \sqrt{R^{2}+\left ( XL - Xc \right )^{2}}

Z = \sqrt{45^{2}+\left ( 56.57-14.14 )^{2}} = 61.85 ohm

Thus, the impedance at double the resonant frequency is 61.85 ohm.

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3 years ago
Explain four different types of fitness technologies that are used to help improve your fitness level.
irina1246 [14]

Answer: endurance, strength, balance, flexibility

Explanation:

walking, jogging, swimming, biking

4 0
1 year ago
Which crop does best in cool temperatures? tomatoes corn cabbage bell peppers 3. Which crop does best in a sandy soil? celery sp
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2 years ago
Great Sand Dunes National Park in Colorado is famous for its giant sand dunes. Sand dunes are landforms that are found in desert
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Answer:

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2 years ago
Combine newton's 2nd law and hooke's law for a spring to find the acceleration of the block a(t as a function of time.
USPshnik [31]
2nd law: F = ma 
hook's law: F = -kx

ma = -kx
a = \frac{d^2x}{dt^2} = - \frac{k}{m} x

try solution: x = e^{ \lambda t} , \frac{dx}{dt} = \lambda e^{ \lambda t}, \frac{d^2x}{dt^2} = \lambda^2 e^{ \lambda t}

\lambda^2e^{ \lambda t}= - \frac{k}{m}e^{ \lambda t}

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