Acceleration of gravity is proportional to 1/D² .
('D' is the distance from the Earth's center.)
We need (D / R)² = 9.8
('R' is the Earth's radius.)
D/R = √9.8 = 3.13
Distance from Earth's <u>center</u> = 3.13 R
Distance above Earth's <u>surface</u> = 2.13 R = about 13,570 km =====================================================
<span>Accelerarea de gravitate este proporțională cu 1 / D².
('D este distanța de centrul Pământului.)
Avem nevoie de (D / R) ² = 9,8
('R' este raza Pământului.)</span><span>
D / R = √9.8 = 3,13
Distanța de la <u>centrul</u> Pamantului = 3,13 R
Distanța de deasupra <u>suprafetei</u> Pamantului = 2.13 R = aproximativ <span><em>13,570 km</em></span></span>
Answer:
normal force, the pluck will move off in a different direction
Explanation:
Answer:
Thank you and please rate me as brainliest as it will help me to level up
You can find
1) time to hit the ground
2) initial velocity
3) speed when it hits the ground
Equations
Vx = Vxo
x = Vx * t
Vy = Vyo + gt
Vyo = 0
Vy = gt
y = yo - Vyo - gt^2 / 2
=> yo - y = gt^2 / 2
1) time to hit the ground
=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2
=> t = √1.631 s^2 = 1.28 s
2) initial velocity
Vxo = x / t = 6.5m / 1.28s = 5.08 m/s
3) speed when it hits the ground
Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s
V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2
=> V = √ (183.56 m^2 / s^2) = 13.55 m/s
It means the speed of the object is increasing
and
there is a positive acceleration in the direction of the velocity
hence
there is a force acting on the object, in the direction of the velocity
