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FrozenT [24]
3 years ago
5

Can someone help me with this I do not understand it? ​

Mathematics
1 answer:
N76 [4]3 years ago
5 0

Answer:

So, the first one is not proportional and therefore has no multiplier.

You are right on the second on both counts!

Step-by-step explanation:

You just need to divide the x's by the y's (individually) in order to determine what they are multiplied by. And the answers you get for the first one will be 5, 6, and 7. Because the numbers are different, they are not proportional.

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For the following pair of functions, find (f+g)(x) and (f-g)(x).
ch4aika [34]

Given:

The functions are

f(x)=4x^2+7x-5

g(x)=-9x^2+4x-13

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The functions (f+g)(x) and (f-g)(x).

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We know that,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x^2+7x-5-9x^2+4x-13

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And,

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7 0
3 years ago
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There are no numbers that are both prime and square.
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