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Sonbull [250]
3 years ago
10

Please, I need help finding the area of this!!

Mathematics
2 answers:
Elza [17]3 years ago
7 0
5*1=5
5*1=5
2*2=4
4+5+5=
14
loris [4]3 years ago
6 0
1) 5×4=20mm
2)3×2=6mm
The area=20-6
=14mm
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1 2/5 fraction that have the same value ​
VladimirAG [237]

Answer:

7/5

Step-by-step explanation:

1 2/5, a mixed number, is equivalent to 7/5.

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If a famer plows 2 acres every 3 hours how long will it take to plow 60 acres
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1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
Simplify <br><img src="https://tex.z-dn.net/?f=%20%20%5Csqrt%7B%20-%20180%7D%20" id="TexFormula1" title=" \sqrt{ - 180} " alt="
QveST [7]

Answer: (6\sqrt{5})i

This is the same as saying 6i\sqrt{5}

====================================================

Work Shown:

\sqrt{-180} = \sqrt{-1*36*5}\\\\\sqrt{-180} = \sqrt{-1}*\sqrt{36}*\sqrt{5}\\\\\sqrt{-180} = i*6*\sqrt{5}\\\\\sqrt{-180} = 6i\sqrt{5}\\\\\sqrt{-180} = (6\sqrt{5})i\\\\

where i = \sqrt{-1}

As the steps show above, the idea is to factor the radicand into smaller pieces where one of those pieces is the largest perfect square possible. In this case, 36 is the largest factor of 180 that's a perfect square. Then I used the rule \sqrt{A*B} = \sqrt{A}*\sqrt{B} to break up the root.

The parenthesis used at the very end is to help separate the 6\sqrt{5} from the i term. The "i" is not under the square root.

4 0
3 years ago
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