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3 years ago

Please, I need help finding the area of this!!

Mathematics

2 answers:

Elza [17]3 years ago

7 0

5*1=5
5*1=5
2*2=4
4+5+5=
14

loris [4]3 years ago

6 0

1) 5×4=20mm
2)3×2=6mm
The area=20-6
=14mm

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sattari [20]

Answer:

Emily will receive 40 cents in return

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2 years ago

Which operation could we perform in order to find the number of milliseconds in a year? 60 * 60 * 24 * 7 * 365 1000 * 60 * 60 *

Tom [10]

Use the following abbreviations:
y = year,
d = day,
h = hour,
min = minute,
s = second,
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Then
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2 years ago

Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters. What is the diagonal d

jolli1 [7]

Answer:

70.7 meters.

Step-by-step explanation:

We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.

Since we know that diagonal of a square is product of side length of square and $\sqrt{2}$ . So we will find diagonal of our given square plaza by multiplying 50 by $\sqrt{2}$ .

$\text{Diagonal distance across the plaza}=50\times \sqrt{2}$

$\text{Diagonal distance across the plaza}=50\times 1.414213562373095$

$\text{Diagonal distance across the plaza}=70.71067811865475\approx 70.7$

Therefore, diagonal distance across the plaza is 70.7 meters.

8 0

2 years ago

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$