I want to believe you mean we find the vertices of the vertices <span>P(−3, −4), Q(3, 4), and R(−6, −3) under a reflection on X=0.
Line X=0 is the y-axis. So for reflection under this axis the y coordinates does not change but the x coordinates only change the sign.
For example, for a point A(x, y) its image under RX=0, A'(-x,y)
A(x, y) </span>⇒ A'(-x, y)
P(−3, −4) ⇒ P'(3, -4)
Q(3, 4) ⇒ Q'(-3, 4) and
R(−6, −3) ⇒ R'(-6, -3)
<span>
</span>
Step-by-step explanation:
24% = 156
1% = 24%/24 = 156/24 = 6.5
100% = 1%×100 = 6.5×100 = 650
so, 650 students were surveyed.
Answer:
y + 1 = 2(x+1)
Step-by-step explanation:
hope this helps
Answer:
sorry, but you need to show the selectings
Step-by-step explanation:
Answer: (b) exactly one plane contains a given line and a point not on the line.
Step-by-step explanation: The basic postulates of geometry are very-well known to all of us. For example-
(i) The intersection of two lines determines a point,
(ii) Two parallel lines give result to a plane,
(iii) A line and a point not on the line determines a plane, etc...
Thus, with the help of the third point, we can easily arrive at the conclusion that a given line and a point not lying on the line is contained in a plane. For example- see the attached figure, AB is a line and P is any point not on the line. They both contained in the plane ABC.
Hence, the correct option is (b).