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nexus9112 [7]
3 years ago
5

What is degenerate circle

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0
It is the circle which has its radius a 0units and it can also be called as a point circle.
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I need you to help me solve this
Svet_ta [14]
For the expression to be factor-able the Discriminant  , has to be greater or equal to zero
ax^2 + cx + b = 0


c^2 - 4 ab >= 0 

(-3)^2 - 4 * 1 * b >= 0

9 - 4b >= 0

9 >= 4b

b <= 9/4  (2.25)

Pick any value in that range for ex:

0 , 2,  -3, -6

7 0
3 years ago
Which equation has roots of 3plus or minus sqare rt 2?
vichka [17]

Answer:

Option D is correct.

The equation with roots 3 plus or minus square root 2 is x² - 6x + 7

Step-by-step explanation:

The roots of the unknown equation are

3 ± √2, that is, (3 + √2) and (3 - √2)

The equation can then be reconstructed by writing these roots as the solutions of the quadratic equation

x = (3 + √2) or x = (3 - √2)

The equation is this

[x - (3 + √2)] × [x - (3 - √2)]

(x - 3 - √2) × (x - 3 + √2)

x(x - 3 + √2) - 3(x - 3 + √2) - √2(x - 3 + √2)

= x² - 3x + x√2 - 3x + 9 - 3√2 - x√2 + 3√2 - 2

Collecting like terms

= x² - 3x - 3x + x√2 - x√2 - 3√2 + 3√2 + 9 - 2

= x² - 6x + 7

Hope this Helps!!!

6 0
3 years ago
Beth bought 5 packs of baseball cards. There are c cards in each pack. Write an expression that shows how many baseball cards Be
Amanda [17]
Beth bought 5 * C baseball cards
8 0
3 years ago
Read 2 more answers
A right rectangular container is 10 cm wide and 24 cm long and contains water to a depth of 14cm. A stone is placed in the water
Simora [160]

Answer:

1356cm3

Step-by-step explanation:

when the stone is dropped in to the water the new height is 17.4cm(14+3.4)

find the volume when the height is 14cm and when the height is 17.4cm

24*14*17.4=4716

24*14*14=3360

then subtract the two volumes

4716-3360=1356cm3

4 0
3 years ago
Read 2 more answers
Least common denominator?
Over [174]

Answer:

\large\boxed{(s-2)(s+2)(s-3)=(s^2-4)(s-3)=s^3-3s^2-4s+12}

Step-by-step explanation:

s^2-4=s^2-2^2=(s-2)(s+2)\\\\\text{used}\ a^2-b^2=(a-b)(a+b)\\\\s^2-5s+6=s^2-2s-3s+6=s(s-2)-3(s-2)=(s-2)(s-3)\\\\\text{Therefore}\ LCD(s^2-4,\ s^2-5s+6)=(s-2)(s+2)(s-3)

4 0
3 years ago
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