Name an example of another disorder that could be caused by a nutritional deficiency.
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Answer:
The phenotypes are as follows
Purple, full- 9
Purple, constricted- 3
White, full- 3
White, constricted- 1
Genotype of parents are PpFf, each produce the following gametes: PF, Pf, pF and pf.
Explanation:
This is a dihybrid cross involving two distinct genes. One coding for flower color and the other for pod shape. The allele for purple color (P) is dominant over the allele for white color (p) while the allele for full pod (F) is dominant over the allele for constricted pod (f).
In a cross between two heterozygote parents i.e. PpFf × PpFf, each parent will produce the following gametes: PF, Pf, pF and pf. Using these gametes in a punnet square (see attached image) the following 16 offsprings will be produced in a phenotypic ratio: 9:3:3:1
Purple color, full pod- 9
Purple color, constricted pod- 3
White flower, full pod- 3
White flower, constricted pod- 1
Answer:
See the answer below
Explanation:
Using the formula for calculating Chi square ():
=
where O = observed frequency and E = expected frequency.
The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.
For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.
Hence, expected frequencies are calculated as:
phenotype (1) = 9/16 x 293 = 164.81
phenotype (2) = 3/16 x 293 = 54.94
phenotype (3) = 3/16 x 293 = 54.94
phenotype (4) = 1/16 x 293 = 18.31
The is calculated thus:
Phenotype O E
1 88 164.81 = 35.80
2 62 54.94 = 0.91
3 62 54.94 = 0.91
4 81 18.31 = 214.64
Total = 35.80 + 0.91 + 0.91 + 214.64 = 252.26
To the nearest tenth = 252
Degree of freedom = n - 1 = 4- 1 = 3
tabulated = 7.815
<em>The calculated </em><em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>