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Artist 52 [7]
3 years ago
13

The coordinate plane shows the floor plan for a swimming pool. What is the area of the pool’s border? A. 50 square meters B. 65

square meters C. 80 square meters D. 100 square meters E. 125 square meters Reset Next
Mathematics
1 answer:
podryga [215]3 years ago
7 0

Answer: Choice B

Step-by-step explanation:

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Answer:

1

Step-by-step explanation:

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A certain truck weighs 2 metric tons A person weighing 60 kg get in the truck followed by a 70 kg person how many kilograms does
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The truck now weighs 2130 kilograms. Hope this helps.
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Kelly spends 3/8 of her free time playing soccer. what percent of her free time was spent playing soccer?
lozanna [386]
I think it's 37.5 . I'm pretty sure cause I think you divide 3/8 . Then you go 2 to the right for your answer with the decimal. Not sure but . I think I'm right.
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3 years ago
What are the solutions to the equation 3(x – 4)(x + 5) = 0
Ne4ueva [31]

Answer:

x=4

x=-5

Step-by-step explanation:

in order for this to be equal to 0, 1 or both of the factors has to be 0, because anything multiplied by 0 is 0.

123 * 29382 * 8139* 0 = 0

x-4 = 0

x = 4

x+5 = 0

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7 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
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