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cestrela7 [59]
3 years ago
13

1.In the outline find your section on soil horizons. In it you will find a diagram representing a view of a soil cut away. Which

of the layers in this example represents the horizon that is alive with roots, fungi, bacteria, worms, small arthropods like spiders and so on?
A. O
B. A
C. B
D. C

2.In the outline find your section on soil horizons. In it you will find a diagram representing a view of a soil cut away. Which of the layers in this example represents the horizon that is very thin and contains large amounts of organic matter?
A. O
B.A
C.B
D.C


3.True or false: In the outline find your section on soil horizons. In it you will find a diagram representing a view of a soil cut away. Horizon B in this example would be very difficult for soil organisms to move through because it would be a very hard layer.
A. True
B.False
Chemistry
1 answer:
gogolik [260]3 years ago
3 0
What grade level 
 is this?
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g n the Ideal Gas Law lab, how is the temperature of the hydrogen gas determined? Select one: The pressure of the gas is determi
Charra [1.4K]

Answer:

The volume of the gas is determined, which will allow you to calculate the temperature.

Explanation:

According to Charles law; the volume of a given mass of an ideal gas is directly proportional to its temperature at constant pressure.

This implies that, when the volume of an ideal gas is measured at constant pressure, the temperature of the ideal gas can be calculated from it according to Charles law.

Hence in the Ideal Gas Law lab, the temperature of an ideal gas is measured by determining the volume of the ideal gas.

4 0
3 years ago
Which molecular solid would have the highest melting point?
TEA [102]

Answer:

Choice B. The solid with hydrogen bonding.

Assumption: the molecules in the four choices are of similar sizes.

Explanation:

Molecules in a molecular solid are held intact with intermolecular forces. To melt the solid, it is necessary to overcome these forces. The stronger the intermolecular forces, the more energy will be required to overcome these attractions and melt the solid. That corresponds to a high melting point.

For molecules of similar sizes,

  • The strength of hydrogen bonding will be stronger than the strength of dipole-dipole attractions.
  • The strength of dipole-dipole attractions (also known as permanent dipole) will be stronger than the strength of the induced dipole attractions (also known as London Dispersion Forces.)

That is:

Strength of Hydrogen bond > Strength of Dipole-dipole attractions > Strength of Induced dipole attractions.

Accordingly,

Melting point due to Hydrogen bond > Melting point due to Dipole-dipole attractions > Melting point due to Induced Dipole attractions.

  • Induced dipole is possible between all molecules.
  • Dipole-dipole force is possible only between polar molecules.
  • Hydrogen bonds are possible only in molecules that contain \rm H atoms that are bonded directly to atoms of \rm F, \rm O, or \rm N.

As a result, induced dipoles are the only force possible between molecules of the solid in choice C. Assume that the molecules are of similar sizes, such that the strengths of induced dipole are similar for these molecules.

Melting point in choice B > Melting point in choice D > Melting point in choice A and C.

8 0
3 years ago
What is ciraquil is medicen
kaheart [24]
This might help you hope so

6 0
3 years ago
Helium and nickel are examples of ________. These
emmasim [6.3K]

Answer:

Elements, in turn, are pure substances—such as nickel, hydrogen, and helium—that make up all kinds of matter.

Hope This Helps!       Have A Nice Day!!

3 0
3 years ago
What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N
Citrus2011 [14]
<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.22 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{1 \ mol \ Mg_3N_2}{3 \ mol \ Mg})(\frac{100.95 \ g \ Mg_3N_2}{1 \ mol\ Mg_3N_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 1.68873 \ g \ Mg_3N_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

8 0
3 years ago
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