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marusya05 [52]
3 years ago
9

The pressure in an automobile tire is 2.0 atm at 27°C. At the end of a journey on a hot summer day the pressure has risen to 2.2

atm. What is the temperature of the air in the tire? a. 272.72 K b. 330 K c. 0.014 K d. 175 K
Chemistry
1 answer:
Kruka [31]3 years ago
3 0

Hey there!

For this we can use the combined gas law:

\frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2}}

We are only working with pressure and temperature so we can remove volume.

\frac{P_{1} }{T_{1}} = \frac{P_{2} }{T_{2}}

P₁ = 2 atm

T₁ = 27 C

P₂ = 2.2 atm

Plug these values in:

\frac{2atm}{27C} = \frac{2.2atm}{T_{2}}

Solve for T₂.

2atm = \frac{2.2atm}{T_{2}}*27C

2atm * T_{2}={2.2atm}*27C

T_{2}={2.2atm}\div2atm*27C

T_{2}=1.1*27C

T_{2}=29.7C

Convert this to kelvin and get 302.85 K, which is closest to B. 330 K.

Hope this helps!

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