Covalent compounds are generally not very hard because they are formed by two or more nonmetallic atoms.
<h3>COVALENT COMPOUNDS:</h3>
Covalent compounds are compounds whose constituent elements are joined together by covalent bonds.
Covalent bonding occurs when two or more nonmetallic atoms of an element share valence electrons. This means that covalent compounds will not be physically hard since they constitute non-metals.
Examples of covalent compounds are:
- H2 - hydrogen
- H2O - water
- HCl - hydrogen chloride
- CH4 - methane
Learn more about covalent compounds at: brainly.com/question/21505413
Answer:
90.26%
Explanation:
From the question given above, the following data were obtained:
Theoretical yield of AlCl₃ = 1551 g
Actual yield of AlCl₃ = 1400 g
Percentage yield =?
The percentage yield of the reaction can be obtained as follow:
Percentage yield = Actual yield / Theoretical yield × 100
Percentage yield = 1400 / 1551 × 100
Percentage yield = 140000 / 1551
Percentage yield = 90.26%
Thus, the percentage yield of the reaction is 90.26%
Balanced chemical equation for the reaction is:
2S
(g) +
(g)+ 2
O (l) ⇒
Moles of
formed is 5.75 moles.
Moles of oxygen used is 5.75 moles in the reaction.
Explanation:
Data given:
moles of S
= 11.5 moles
moles of
= ?
Moles of
needed =?
balanced equation with states of matter =?
Balanced chemical reaction under STP condition is given as:
2S
(g) +
(g) + 2
O (l) ⇒
From the balanced reaction 2 moles of sulphur dioxide reacted to form 1 mole of sulphuric acid:
so, from 11.5 moles of S
, x moles of
is formed

2x = 11.5
x = 5.75 moles of sulphuric acid formed.
From the balanced reaction 1 mole of oxygen reacted to form 1 mole of sulphuric acid.
when 11.5 moles of Sulphur dioxide reacted then oxygen in the reaction is 5.75 moles.
The value of X is 2
The total amount of sample taken is 2.00 g
The amount of sample left in the oven after drying is 1.565g
The amount of sample lost (mass of water driven out) = Total sample-Anhydrous salt left in the oven
= 2.00 - 1.565
= 0.435 grams
The moles of anhydrous salt present in the hydrate = 1.565g/129.83g/mol = 0.01205
The moles of water present in the hydrate = 0.4350g/18.01g/mol = 0.02415
Therefore the ratio of these two are in 1:2 ratio
The complete chemical reaction is CoCl2.2H20
To know more about the Similar calculation and explanation click here:
brainly.com/question/14967837
#SPJ4