The answer is high melting and boiling points. Because alkali metals have a range of melting points from a high of 179 °C (354 °F) for lithium to a low of 28.5 °C (83.3 °F) for cesium

- From the first mechanism, it can be seen that the Aluminum is reduced at cathode and Florine is oxidized at anode.
- The ratio of aluminium and fluorine is the ratio of their change in oxidation number, i.e. 2:3
<em><u>༒</u></em><em><u>H</u></em><em><u>O</u></em><em><u>P</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>H</u></em><em><u>E</u></em><em><u>L</u></em><em><u>P</u></em><em><u>S</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u>༒</u></em>
<em><u>༒</u></em><em><u>M</u></em><em><u>A</u></em><em><u>R</u></em><em><u>K</u></em><em><u> </u></em><em><u>M</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>S</u></em><em><u> </u></em><em><u>B</u></em><em><u>R</u></em><em><u>A</u></em><em><u>I</u></em><em><u>N</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>S</u></em><em><u>T</u></em><em><u>༒</u></em>
Answer:
80grams
Explanation:
RAM of O=16
molar mass of O2= 16×2=32g/mol
mass= mole × molar mass
= 2.5×32= 80g
433.8267 g/mol according to Chemical aid