We will use additional formula:
sin ( 90°+ theta ) = sin 90° * cos(theta) + cos 90° * sin(theta)=
= 1 * cos(theta) + 0 * sin(theta)= cos (theta) It is proved.
<span>
Slope = 3
x-intercept = 28/3 = 9.33333<span>
y-intercept = 28/-1 = -28.00000
Hope this helped</span></span>
Recall what a parallel line is; two lines that are parallel are defined as having the same gradient or slope. Consider a line:
y = mx + b
If we want to find a certain line that is / parallel / to the original line passing through an arbitrary point (x₁, y₁), it is useful to understand the point-gradient or point-slope formula.
The gradient to the line y = mx + b is simply m. So, any parallel line to y = mx + b will have the same gradient. Examples include: y = mx + 1, y = mx + 200, y = mx + g
All we need to know, now, is to identify what specific line hits the desired point. Well, the point-gradient formula can help with that. Recall that the point-gradient formula is:
y - y₀ = m(x - x₀), where (x₀, y₀) is the point of interest.
Hence, it is useful to use the point-slope formula when asked for a point and a set of parallel lines to the original line.
Answer:
reflections, translations and rotations
Step-by-step explanation:
Yes.
