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aev [14]
3 years ago
6

3x^3+20x^2-21x+88 divided (x+8) using long division

Mathematics
1 answer:
elixir [45]3 years ago
8 0

Answer:

3 x 4 + 44 x 3 + 139 x 2 − 168 x + 88 /x + 8

Step-by-step explanation:

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atroni [7]

Answer:

factors ?

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The volume of a cube is 216 ft. What is the length of a side?
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Which is the completely factored form of 4x3 10x2 – 6x? 2(x 3)(2x – 1) 2x(x 3)(2x – 1) 2x(x – 3)(2x – 1) 2(x – 3)(2x 1).
Natalija [7]

The equation 4x^3+10x^2 – 6x is factorized as 2x(x+3)(2x – 1).

Option B represents the correct factors of the equation.

<h3>What is a Factor of the number?</h3>

A factor of the number can be defined as a divisor of the number that divides it completely without leaving any remainder.

Given equation is 4x^3+10x^2 – 6x. This can be factorized as given below.

4x^3+10x^2-6x = 0

We take the common term 2x, then,

2x ( 2x^2 + 5x -3)=0

2x ( 2x^2 +6x -x -3)=0

2x (2x (x+3) -1(x+3))=0

2x (2x-1)(x+3)=0

Hence we can conclude that the factors of the given equation are 2x(x+3)(2x – 1). Option B shows the correct factors.

To know more about the factors, follow the link given below.

brainly.com/question/3423184.

6 0
3 years ago
Two number cubes are rolled for two separate events: 
MatroZZZ [7]

Let us first make the sample space for the event A. The Sample Space will be:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

As can be clearly seen the Sample Space for the event A has 30 elements in it.

Now, it is given in the question that the event A has already occurred and we need to find the probability of the event B occurring <u><em>given that the event A has already occurred.</em></u>

Now, as we can see, from the sample space, only 11 events out of the 30 are the events of interest to us. This is shown in bold below:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

Thus, the probability that the event B occurs given that the event A has already occurred is:

P(B|A)=\frac{11}{30}\approx0.367

In percentage the required probability is 36.7% approximately.

3 0
3 years ago
A student is studying a population of 100 Daylilies by the roadside. The plants in this population are genetically variable. The
Murljashka [212]

Answer:

broad sense heritability = 0.75

Step-by-step explanation:

Step 1: Variables

phenotypic variation (Vp)

genotype variation (Vg)

environment variation (Ve)

broad sense heritability (H)

Step 2: Formulas:

H = Vg / Vp

Vp = Vg + Ve

Vg = Vp - Ve

Step 3: Given data

Vp = 20

Ve = 5

Step 4: Computation

Vg = 20 - 5 = 15

H = 15 / 20

H = 0.75

Hope this helps!

5 0
3 years ago
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