$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$

$\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM$

Hence there is no such natural numbers exist.

7 0

2 years ago

A bag contains 42 red, 45 green, 20 yellow, and 32 purple candies, you pick one candy at random, find the probability that it is

Gnesinka [82]

Answer:

P (green/yellow) = 65/139

Step-by-step explanation:

42 + 45 + 20 + 32 = 139 possibilities

45 + 20 = 65 desired outcomes

65/139

Hope this helps!

3 0

3 years ago

Please please help I don’t understand

9966 [12]

Answer:

2x+3y= 1500

Step-by-step explanation:

8 0

3 years ago