i cant tell you that it is from a test
Answer:
Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)
- 6k + 7k = 1k = k
(7 - 6 = 1)
12r - 8 - 12 = 12r - 20
(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.
n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13
(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)
- 4x - 10x = 14x
(10 + 4 = 14)
- r - 10r = 11r
(r = 1 so 10 + 1 = 11)
Well when you round to the nearest 10 it will be 1 number after the point (this is due to that 10 only has one 0.) now we know that if there is a number bigger than 5 besides the number they ask you in this case the first after the point you will add 1 to that number. in this case you will add 1 to the 3. this will give you the answer of 56.4
Hope this helps
Answer:
Yes
Step-by-step explanation:
using pythagorus theorum: a^{2} + b^{2} = c^{2}
24^{2} +32^{2} = 1024+576
= 1600
40^{2} = 1600
thus, it can be concluded that these lengths can be the sides of a right-angled triangle.
