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3 years ago

Find the mean, median, and mode for the following scores: 8, 7, 5, 7, 0, 10, 2, 4, 11, 7, 8, 7

Mathematics

1 answer:

marusya05 [52]3 years ago

4 0

Answer:

mode is 7, mean, 6.3 repeating, median 7

Step-by-step explanation:

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Find each quotient using long division 676 ÷ 13 (need the full thing fast lol)

ra1l [238]

Answer:

Step-by-step explanation:

Ok then "cracks knuckles" heres an image of the division! hope it helps.

3 0

2 years ago

Someone please help ASAP will give brainliest

algol13

√0.02 is rational

√2 is rational

√2 is irrational

√1/2 is rational

6 0

3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Jobisdone [24]

Answer:

$f(x)=x^4-9x^2-50x-150$

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is $f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))$

We expand to get: $f(x)=(x^2-2x-15)(x^2+2x+10)$

We expand further to get:\

$f(x)=x^4-9x^2-50x-150$

3 0

3 years ago

which linear system has been correctly solved for one of the variables from the following system? 2x - y = -1 2x y = -7 2x - y =

mr Goodwill [35]

If you would like to solve the system of linear equations, you can do this using the following steps:

2x - y = -1 ... y = 2x + 1
2x + y = -7 ... y = -7 - 2x

The correct result would be: y = 2x + 1, <span>2x + y = -7.</span>

4 0

3 years ago

A simple random sample of 20 third-grade children from a certain school district is selected, and each is given a test to measur

ICE Princess25 [194]

Answer:

Option C) 5.62 points

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Sample mean score = 64

Sample standard deviation, s = 12

Degree of freedom =

$=n-1\\=20-1\\=19$

We have to calculate margin of error for a 95% confidence interval.

Formula for margin of error:

$t_{critical}\times \displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.05} = \pm 2.093$

$2.093\times (\displaystyle\frac{12}{\sqrt{20}} )\\\\ =5.6161\approx 5.62$

Thus, the correct answer is

Option C) 5.62 points

4 0

3 years ago