Answer:
10 years
Step-by-step explanation:
I think the answer is 14.
the smallest common multiple of 6 and 9 is 18. all multiples of 18 is divisible by 6 and 9.
500 ÷18=27.777777777
there are 27 numbers between 1 and 500 that are divisible by both 6 and 9, but when the quotient is an even number, the multiple of 18 is divisible by 4 as well, so only the multiples of 18 that produce an odd quotient satisfy the requirement.
from 1 to 27, there are 14 odd numbers.
Answer:
(-1, -1) and (2, 2)
Step-by-step explanation:
Substitute for y in the first equation and solve the quadratic.
x = x^2 -2
x^2 -x -2 = 0 . . . . subtract x
(x -2)(x +1) = 0 . . . .factor
Solutions are the values of x that make these factors be zero:
x = 2, x = -1
Since y=x, the solutions are ...
(x, y) = (-1, -1) and (2, 2)
Answer: Option C. Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Solution:
Conditional relative frequency single employees in grade 2:
[(Single employees in job grade 2)/(Total employees in job grade 2)]*100%=
(222/4,239)*100%=0.052370842*100%=5.2370842% approximately 5.2%
Conditional relative frequency married employees in grade 2:
[(Married employees in job grade 2)/(Total employees in job grade 2)]*100%=
(3,927/4,239)*100%=0.926397735*100%=92.6397735% approximately 92.6%
92.6%>5.2%:
Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
147,300,000.....1 million more is : 148,300,000
