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3 years ago

HELP ASAP!! ITS DUE

Mathematics

1 answer:

Hunter-Best [27]3 years ago

6 0

Answer:

The surface area of a solid object is a measure of the total area. Find the area of all the sides and add them up.

Area of rectangles:

40+40+16+16= 112

split the pentagon so they will be a reactangle and a triangle.

6-2=4. The height of the triangle is 4.

3+3=6, 6*2=12. 12 is the area of the mini rectangles, 12*2=24. 24 is the total area for both the mini rectangles.

Area of the triangle is 12.

Add them all up:

112+12+24= 148

148

<em>Hope this helps!!</em>

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4 years ago

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For the differential equations dydx=sqrt(y^2−36) does the existence/uniqueness theorem guarantee that there is a solution to thi

julsineya [31]

Answer:

1. (-4,6) there is no a solution to the equation through this point

2. (2,−6) there is no a solution to the equation through this point

3. (−5,39) there is a solution to the equation through this point

4. (−1,45) there is a solution to the equation through this point

Step-by-step explanation:

Using the existence and uniqueness theorem:

Let:

$F(x,y)=\sqrt{y^2-36} \\\\and\\\\\frac{\partial F}{\partial y} =\frac{y}{\sqrt{y^2-36} }$

Now, let's find the domain of $F(x,y)$ , due to the square root:

$y^2-36 \geq 0\\\\y^2\geq 36\\\\y \geq 6\hspace{12}or\hspace{12}y\leq-6$

So the domain of the function is:

$y \in R\hspace{12}y\geq6\hspace{12}or\hspace{12}y\leq-6$

Now, due to the fraction $\frac{\partial F}{\partial y}$ the denominator must be also different from 0, so:

$y^2-36\neq0\\\\y \neq \pm6$

So, the theorem tells us that for each $y_0\in R:\hspace{12}y_0>6\hspace{12}or\hspace{12}y_0$ there exists a unique solution defined in an open interval around $x_0$ .

1. (-4,6) there is no a solution to the equation through this point because $y_0=6$

2. (2,−6) there is no a solution to the equation through this point because

$y_0=-6$

3. (−5,39) there is a solution to the equation through this point because

$y_0>6$

4. (−1,45) there is a solution to the equation through this point because

$y_0>6$

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3 years ago

What is greater 0.48 or 6/15

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