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kakasveta [241]
3 years ago
15

Need help with this !!!!!!

Mathematics
1 answer:
SVEN [57.7K]3 years ago
6 0

Answer:

25+7(n-1)

Step-by-step explanation:

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Solve the problem attached in the image
EleoNora [17]

Answer:

no te entiendo

yo también la busco

4 0
3 years ago
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If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

Thus,

t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0
2 years ago
Value of p,q and r if (2^p)*(3^q)*(7^r)=1176
koban [17]

Answer:

p=3 , q=1 , r=2

Step-by-step explanation:

1176=2*2*2*3*7*7

1176=(2^3)*(3^1)*(7^2)

given that 1176 = (2^p)*(3^q)*(7^r)

Comparing Equation 1 & 2

we get p=3 , q=1, r=2

5 0
3 years ago
Mr. canton places 24 desks in 6 equal rows. how many is in each row?? is it 24 times 6
lisabon 2012 [21]
24/6=4. 4 desks in each row.
3 0
2 years ago
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One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t
Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) M = \frac{8*3 + 16*5}{3+5}= 13

c) M = \frac{8*5 + 16*3}{5+3}= 11

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

M = \frac{8*3 + 16*5}{3+5}= 13

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

M = \frac{8*5 + 16*3}{5+3}= 11

7 0
3 years ago
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