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kakasveta [241]
3 years ago
15

Need help with this !!!!!!

Mathematics
1 answer:
SVEN [57.7K]3 years ago
6 0

Answer:

25+7(n-1)

Step-by-step explanation:

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On monday marco practiced the piano for 7/10 hour. On Tuesday he practiced for 1 1/4 hours each day write a question that involv
Fantom [35]

Step-by-step explanation:

Since we have given that

Number of hour Marco practiced the piano on Monday is given by

\frac{7}{10}

Number of hours Marco practiced the piano on Tuesday is given by

1\frac{1}{4}=\frac{5}{4}\ hours

1) For Adding :

Total number of hours he practiced on both Monday and Tuesday will be

\frac{7}{10}+\frac{5}{4}\\\\=\frac{14+25}{20}\\\\=\frac{39}{20}\ hours

2) For Subtraction,

Number of hour he practiced more on Tuesday than on Monday will be

\frac{5}{4}-\frac{7}{10}\\\\=\frac{25-14}{20}\\\\=\frac{9}{20}\ hours


4 0
3 years ago
Read 2 more answers
Which set of points is a function?
mario62 [17]

Answer:

B

Step-by-step explanation:

This is a really simple topic. All you need to do when seeing these ordered pairs is see which has x-values that don't repeat. Over here, we can see that that is B, so B is the correct option.

5 0
2 years ago
The equation of a line is given by, 13x – y + 12 = 0. Find the slope and both the intercepts.​
MArishka [77]

Answer:

The slope is 13.

The x intercept is x=\frac{-12}{13}.

The y intercept is y=12.

Step-by-step explanation:

1. Finding the slope.

This is a linear equation, because <u>it's graph forms a line</u>. In a linear equation, the slope is always the value that multiplies x. In this case, x is being multiplied by 13, therefore, <u>the slope is 13</u>.

2. Finding the x intercept.

The x intercept is found when the value of y is 0. Let's replace the value of y for 0 in the equation and solve the x:

13x-y + 12 = 0\\\\13x-(0) + 12 = 0\\\\13x+12 = 0\\\\13x= -12\\\\x=\frac{-12}{13}

<u>The x intercept is </u>x=\frac{-12}{13}<u>.</u>

3. Finding the y intercept.

The y intercept is found when the value of x is 0. Let's replace the value of x for 0 in the equation and solve the y:

13x-y + 12 = 0\\\\13(0)-y + 12 = 0\\\\-y + 12 = 0\\\\-y=-12\\\\y=12

<u>The y intercept is </u>y=12<u>.</u>

3 0
2 years ago
Mrs. Walker is instructing a team of students on designing the sailboat shown. Beth is working on the smaller sail, which is a r
Pachacha [2.7K]

Answer: OPTION C.

Step-by-step explanation:

1. To solve this problem you must apply the Pythagorean Theorem, which is shown below:

a^{2}=b^{2}+c^{2}

Where a is the hypotenuse, and b and c are the legs of the triangle.

2. When you solve for one of the legs and substitute values, you obtain that the result is:

b=\sqrt{a^{2}-c^{2}}\\b=\sqrt{(24.8ft)^{2}-(8ft)^{2}}\\b=23.5ft

5 0
3 years ago
Read 2 more answers
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

3 0
3 years ago
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