Question

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Answer 1

9514 1404 393

Answer:

1. (f×g)(x) = 2x^2 +2x
2. (f×g)(x) = 6y^2 -11y -35

Step-by-step explanation:

The distributive property applies.

1. (fg)(x) = f(x)·g(x) = (2x)·(x +1)

  (f×g)(x) = 2x^2 +2x

__

2. (fg)(x) = f(x)·g(x) = (2y -7)·(3y +5) = 2y(3y +5) -7(3y +5)

  (f×g)(x) = 6y^2 -11y -35

_____

Additional comment

Please note in problem 2 that the function argument is x and the variable in the given expressions is y. This means the function value is exactly and only 6y^2 -11y -35 for any value of x. It does not change when x changes. (We suspect a typo.)

Answer 2

Answer:

9514 1404 393

Answer:

1. (fxg)(x) = 2x^2 +2x 2. (fxg)(x) = 6y^2 -11y -35

Step-by-step explanation:

The distributive property applies.

1. (fg)(x) = f(x)-g(x) = (2x)-(x+1)

(fxg)(x) = 2x^2 +2x

2. (fg)(x) = f(x) g(x) = (2y -7) (3y +5) = 2y(3y +5)

-7(3y +5) (fxg)(x) = 6y^2 -11y -35

Additional comment

Please note in problem 2 that the function argument is x and the variable in the given expressions is y. This means the function value is exactly and only 6y^2 -11y -35 for any value of x. It does not change when x changes. (We suspect a typo.)