All categories

3 years ago

How do you find launch velocity only with time and distance

Physics

1 answer:

Annette [7]3 years ago

3 0

To find initial velocity, start by multiplying the acceleration by the time. Then, divide that number by 2 and write down the quotient you get. Next, divide the distance by the time and write down that quotient as well. Finally, subtract your first quotient from your second quotient to find the initial velocity.

You might be interested in

What has a greatest (most substantial/ most influential) effect on the strength of the force of

xxTIMURxx [149]

Answer:

The force of gravity effected by stream the was muscle in the earth.

Explanation:

It just was

4 0

3 years ago

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

Sedaia [141]

Answer:

$a_2\ =\ -33.65\ m/s^2$

Explanation:

Given,

For the first rocket,

Initial velocity of the first rocket A = $u_1\ =\ 4600\ m/s.$

Acceleration of the first rocket = $a_1\ =\ -18\ m/s^2$

For the second rocket,

Initial velocity of the second rocket B = $u_2\ =\ 8200 m/s.$
Displacement of both the rockets A and B = s = 0 m

Fro the first rocket,

Let 't' be the time taken by the first rocket A for whole the displacement

$\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec$

Let $a_2$ be the acceleration of the second rocket B for the same time interval

from the kinematics,

$\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\$

$\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2$

Hence the acceleration of the second rocket B is -33.65\ m/s^2.

6 0

3 years ago

Which of the following is how the substance in a longitudinal wave flows?

cricket20 [7]

Answer:

The answer is <em>D. In the direction of the wave</em>

Explanation:

I took the test, hope this helps! :)

3 0

3 years ago

A spring whose stiffness is 1140 n/m has a relaxed length of 0.51 m. if the length of the spring changes from 0.26 m to 0.79 m,

Ugo [173]

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
Read more on Brainly.com - brainly.com/question/1581851#readmore

7 0

4 years ago

A Semi truck(m=20,000kg) is 10 m from a car(m=200kg). What is the force of gravity between them(G=6.67*10^-11N•m^2/kg^2)

gregori [183]

Answer:

F = 2.668*10_-6[N]

Explanation:

We can calculate this force using the law of universal gravitation raised by Isaac Newton

$m_{t}=20000[kg]\\m_{c}= 200[kg]\\r = 10[m]\\G = 6.67*10^{-11}[\frac{N*m^{2} }{kg} ] \\$