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omeli [17]
4 years ago
14

What is the differ of fermentation from respirstion

Physics
1 answer:
Andrej [43]4 years ago
8 0
This may help u... :P

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What causes the magnetic field around the wire?
slamgirl [31]

Answer:ITS B

Explanation: TOOK DA TEST AND GOT IT RIGHT NO CAP YOUR WELCOME

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3 years ago
Can someone help me with 1-2
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Can't really plot a graph here for question 1.

2a) The car speeds up from A to B. The car travels at a constant speed from B to C. The car slows down to a stop from C to D.

b) From the graph, at 10 seconds, the car is moving at 20 m/s.
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_____ is the frictional force needed to slow down an object in motion
tekilochka [14]

Answer

gravity

Explanation:

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4 years ago
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10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
Mila [183]

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

   = 0.25 cm

The wire is 0.25 cm thick.

8 0
3 years ago
A barge floating in fresh water (p = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and height H
Karolina [17]

Answer:

a) \Delta m = 330000\,kg, b) h = 1.268\,m

Explanation:

a) According the Archimedes' Principle, the buoyancy force is equal to the displaced weight of surrounding liquid. The mass of the coal in the barge is:

\Delta m \cdot g = \rho_{w}\cdot g \cdot \Delta V

\Delta m = \rho_{w}\cdot \Delta V

\Delta m = \left(1000\,\frac{kg}{m^{3}} \right)\cdot (550\,m^{2})\cdot (1.05\,m-0.45\,m)

\Delta m = 330000\,kg

b) The submersion height is found by using the equation derived previously:

\Delta m = \rho_{w}\cdot \Delta V

450000\,kg = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (550\,m^{2})\cdot (h-0.45\,m)

The final submersion height is:

h = 1.268\,m

4 0
3 years ago
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