The wavelength of the wave is 0.055 m
Explanation:
The relationship between speed, frequency and wavelength of a wave is given by the wave equation:
![v=f\lambda](https://tex.z-dn.net/?f=v%3Df%5Clambda)
where
v is the speed
f is the frequency
is the wavelength
For the sound wave in this problem we have
v = 340 m/s is the speed
f = 6,191 Hz is the frequency
Solving for
, we find the wavelength:
![\lambda=\frac{v}{f}=\frac{340}{6191}=0.055 m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bv%7D%7Bf%7D%3D%5Cfrac%7B340%7D%7B6191%7D%3D0.055%20m)
Learn more about waves and wavelength:
brainly.com/question/5354733
brainly.com/question/9077368
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Answer:2m/s²
Explanation: Well F=MA so sice F=4N and M=2kg let's plug in the values
4N=2KG*A
A=4N/2KG
A=2m/s²
Answer:
27 m/s
Explanation:
Given:
v₀ = 15 m/s
a = 3 m/s²
t = 4 s
Find: v
v = at + v₀
v = (3 m/s²) (4 s) + (15 m/s)
v = 27 m/s
Answer:
124.86 V
Explanation:
We have to first calculate the voltage drop across the copper wire. The copper wire has a length of 358 ft
1 ft = 0.3048 m
358 ft = 109.12 m
The diameter of 2 AWG copper wire (d) = 6.544 mm = 0.006544 m
The area of the wire = πd²/4 = (π × 6.544²)/4 = 33.6 mm²
Resistivity of wire (ρ) = 0.0171 Ω.mm²/m
The resistance of the wire = ![\frac{\rho A}{l}=\frac{0.0171*109.12 }{33.6} =0.056\ ohm](https://tex.z-dn.net/?f=%5Cfrac%7B%5Crho%20A%7D%7Bl%7D%3D%5Cfrac%7B0.0171%2A109.12%20%7D%7B33.6%7D%20%3D0.056%5C%20ohm)
The voltage drop across wire = current * resistance = 6.1 A * 0.056 ohm = 0.34 V
The voltage at end = 125.2 - 0.34 = 124.86 V