How much negative charge has been removed from a positively charged electroscope if it has a charge of 7.5x10-11C?
If C is Coulombs then, −1 C is equivalent to the charge of approximately 6.242×10^18 electrons.
You already gave the answer: -7.5x10–11C
It is like asking: What colour is my white horse?
Now if you want to know how many electrons have been removed, then multiplying the number of electrons in a coulomb by the coulombs you have, you get 4.6815 x 10^8 electrons. Which is almost the same answer as before.
Its bituminous coal good luck :;;;;;;)
Answer:
Explanation:
Hi!
We define the point (0,0) as the intial position of the ball. The initial velocity is
The motion of the ball in the horizontal direction (x) has constant velocity, because there is no force in that direction. :
In the vertical direction (y), there is the downward acceleration g of gravity:
(note the minus sign of acceleration, because it points in the negative y-direction)
When the ball hits the ground, at t = 65s, y(t = 65 s) = 0. We use this to find the value of the initial vertical velocity:
We used that g = 9.8 m/s²
To find the horizonttal component we use the angle:
<span>mechanical energy is E=mgh+ 1/2 mV²=2*9.8*1+1/2*2*4.4²=38.96J,
the only force is P, that is a conservative force so the answer is
</span>mechanical energy is conserved and its value is <span>38.96J, </span>